Lecture 11
Circuit theorem
Circuit theorem
Circuit theorem: Substitution theorem�
Given any branch, if its voltage is u and current is i, it can be replaced by an independent voltage source with voltage u, an independent current source with current i, or a resistor with resistance u/i. After replacement, the voltage or current of all branches in the circuit remain unchanged.
Proof:
A circuit (containing power source)
branchk
+
-
uk
i
A circuit (containing power source)
+
-
uk
i
Circuit theorem: Substitution theorem�
A circuit (containing power source)
branchk
+
-
uk
i
A circuit (containing power source)
+
-
uk
i
A circuit (containing power source)
branch
k
+
-
uk
i
+
-
uk
+
-
uk
uk
+
-
By adding two extra voltage sources, the terminal voltage of A circuit does not change.
1
2
The potential at node 1 and 2 is equal. Thus, node 1 and node 2 can be short-circuited.
Circuit theorem: Substitution theorem�
Example: to solve the current i1 i2 i3 and voltage u
110V
+
-
i2
10Ω
10Ω
+
-
5Ω
5Ω
i1
i3
i1 = 110V / (5 + (5+10)*10/(5+10+10) )=10A
i2 = i1 *0.6 = 6A, i3 = i1 *0.4 = 4A
u = 60V
110V
+
-
i2
10Ω
+
-
5Ω
5Ω
i1
i3
60V
We can easily solve
Suppose we only know the voltage of the 10Ω-resistor, we can replace the resistor with a 60V voltage source. The other quantities can be solved very easily.
Circuit theorem: Substitution theorem�
Note:
After the substitution, there should be no voltage-source loop in the circuit.
10V
+
-
i2
5Ω
+
-
2Ω
i1
i3
5V
10V
+
-
i2
+
-
2Ω
i1
i3
5V
5V
What is i2 and i3?
Circuit theorem: Substitution theorem�
Note:
After the substitution, there should be no joint in the circuit where the current of current-sources meets.
10V
+
-
i2
1Ω
i1
1A
2A
1Ω
1Ω
10V
+
-
i2
1Ω
i1
1A
2A
1Ω
1A
+
-
u
What is u?
Circuit theorem: Substitution theorem�
Example: if we want ix = i1/8, what is the value of the substitute resistance Rx ?
To get the equivalent resistance, it is necessary to solve the voltage u on the resistor.
1Ω
i1
0.5Ω
0.5Ω
0.5Ω
ix
+
1Ω
0.5Ω
0.5Ω
0.5Ω
ix
u(2)
+
-
u(1)
+
-
1Ω
i1
0.5Ω
0.5Ω
0.5Ω
1Ω
i1
0.5Ω
0.5Ω
0.5Ω
ix
Rx
Circuit theorem: Substitution theorem�
u(a) = u(b) + u(1)
So u(1) = u(a) - u(b)
=1Ω * i1 *(1.0/2.5) – 0.5Ω * i1 *(1.5/2.5)
= 0.1 * i1
u(a) + u(b) + u(2) =0
So u(2) = -(u(a) + u(b))
= -(1+0.5)Ω * ix *(1/2.5)
= -0.075 * i1
u = u(1) + u(2) = 0.025 * i1
Rx = u/ix = 0.025 * i1 / 0.125i1 = 0.2Ω
1Ω
i1
0.5Ω
0.5Ω
0.5Ω
1Ω
0.5Ω
0.5Ω
0.5Ω
ix
+
u(1)
u(2)
+
-
+
-
u(a)
u(b)
u(a)
u(b)
Circuit theorem: Substitution theorem�
Assignment: to prove that after the branch is replaced by the current source with current is, the voltage or current of all branches in the circuit remain unchanged.
A circuit (containing power source)
branchk
+
-
uk
i
A circuit (containing power source)
+
-
is
uk
Circuit theorem: Substitution theorem�
Assignment: if uab=0,what is the value of R?
4Ω
i1
R
2Ω
8Ω
20V
+
-
+
-
3V
3Ω
a
b
Circuit theorem: Substitution theorem�
Assignment: If ua= is replaced by a resistor R,what is the resistance value of R to keep the other quantities unchanged?
4Ω
2Ω
2Ω
10Ω
10Ω
4V
ua=2V
3A
+
-
+
-
Circuit theorem: Substitution theorem�
25Ω
4Ω
20Ω
R
10Ω
42V
0.5A
+
-
4Ω
60Ω
30Ω
a
b
c
d
Assignment: if uab=0,what is the value of R?