Arithmetic
Progressions
6, 12, 18, 24, ...
12) Find the sum of first 40 positive integers divisible by 6.
Sol:
The positive integers which are divisible by 6 are
∴ These numbers form an A.P. with a =
6
and d =
6
Sn =
∴ S40 =
=
=
∴ S40 =
∴ S40 = 4920
Difference between consecutive terms
are same
To find S40
For S40 substitute
n = 40, a = 6 & d = 6
∴ Sum of first 40 positive integers divisible by 6 is 4920.
Exercise 5.3 12
with a = 8 and d = 8
Q.13. Find the sum of the first 15 multiples of 8.
Sol:
The multiples of 8 are
These numbers form an A.P
S15 =
∴ S15 = 960
∴ Sum of the first 15 multiples of 8 is 960
8, 16, 24, 32…
Difference between consecutive terms
are same
To find S15
[2(8) + (15 – 1) 8]
For S15 substitute
n = 15, a = 8 & d = 8
[16 + (14) 8]
[16 + 112]
Exercise 5.3 13
HOMEWORK