Mechanical Properties of fluid 1
S. U. Hiswankar PGT(Physics)
Jawahar Navodaya Vidyalaya, Wardha
Fluid:
A fluid (both liquid and gases) is a substance that can flow.
Liquid in equilibrium:
O
S
U
T
W
θ
R
The reaction R can resolve in two components
1) Tangential component OT = R cos θ
2) Normal component OW = R sin θ
component OT = R cos θ = 0
As R ≠ 0 hence cos θ = 0 or θ = 900
i.e. liquid always exerts force perpendicular to the surface of the container at every point.
Measurement of pressure :
P
F
=
A
0
Pascal’s Law:
A change in pressure applied to an enclosed incompressible fluid is transmitted undiminished to every point of the fluid and the walls of the containing vessel.
For equilibrium of fluid element we have
Fb sin θ = Fc
Fb cos θ = Fa
From geometry of figure we have
Ab sin θ = Ac
Ab cos θ = Aa
Fb sin θ
Ab sin θ
=
Fc
Ac
From above equations we get
Fb cos θ
Ab cos θ
=
Fa
Aa
or
Fa
Aa
=
Fb
Ab
=
Fc
Ac
Pa = Pb = Pc
or
Hence pressure exerted in all direction is same
0
f
F
a
A
C1
C2
Liquid
Load
1) Hydraulic lift :
Hydraulic lift is used to lift heavy objects.
Pressure exerted on the liquid
P
f
=
a
Force on larger piston is
F = P x A
F
f
=
a
x A
F
A
=
a
x f
Since A>a, therefore, F > f
Hence by making the ratio A/a large, very heavy load (like cars and trucks) can be lifted.
0
Applications of Pascal’s Law :
2) Hydraulic brakes :
0
P1
P2
h
Variation of liquid pressure with depth :
a) Force due to liquid pressure at the top
F1 = P1A, (↓)
b) Force due to liquid pressure at the bottom
F2 = P2A, (↑)
c) Weight of the cylinder acting downward
W = Mass x g (↓)
W = Volume x density x g
W = Ahρg
As the liquid cylinder is in equilibrium
Net downward force = Net upward force
F1 + W = F2
F2 – F1 = W
P2A – P1A = Ahρg
P2 – P1 = hρg
0
Buoyant force :
The upward force acting on a body immersed in the fluid is called upthrust or buoyant force and the phenomenon is called buoyancy.
ρ
σ
Archimedes principle:
It states that when a body is partially or wholly immersed in a fluid, it experiences an upward thrust equal to the weight of the fluid displaced by it & its upthrust act through the centre of gravity of the displaced fluid.
Apparent weight of immersed body :
Apparent weight = Actual weight – Buoyant force
Wapp = Vσg - Vρg
Wapp = Vσg(1 – ρ/σ)
Wapp = W (1 – ρ/σ)
Law of flotation:
It states that a body will float in a liquid if the weight of the liquid displaced by the immersed part of the body is equal to or grater then the weight of the body.
i) W > U or σ > ρ
body sinks
ii) W = U or σ = ρ
body floats fully immersed
ii) W < U or σ < ρ
body floats partly immersed
σ
σ
σ
ρ
ρ
ρ
0
c
Viscosity :
Viscosity is the property of fluid by virtue of which an internal force of friction comes into play when fluid is in motion and which opposes the relative motion between its different layers.
Fixed surface
F
V = 0
V = maximum
Coefficient of viscosity:
M
v
c
N
v + dv
x
X + dx
Fixed surface
V = 0
According to Newton, a force of viscosity F acting tangentially between two layers
F α A
F α
dv
dx
F α A
dv
dx
F =- η A
dv
dx
{contd….
η is coefficient of viscosity
F
Hence coefficient of viscosity of a liquid may be defined as the tangential viscous force required to maintain a unit velocity gradient between its two parallel layers each of unit area.
Note :
2)
Dimensions of η
[η] = [M1 L-1 T-1]
3) SI unit of η is N s /m2 or Kg /m s or decapoise or poiseuille.
4) CGS unit of η is dyne s /cm2 or g /cm s or poise
0
Effect of temperature on viscosity :
Poiseuille’s formula :
The volume of a liquid flowing out per second through a horizontal capillary tube of length ℓ and radius r, under a pressure difference p applied across its end is given by
Q =
πpr4
8 η ℓ
V
t
=
Stokes’ Law :
The retarding (backward) viscous force acting on a small spherical ball of radius r moving with uniform velocity v through fluid of viscosity η is given by.
F = 6πηrv
The viscous force F acting on a sphere moving through fluid may depends on
i.e.
F = k ηa rb vc
[M1 L1 T-2 ] = [M1 L-1 T-1 ]a [L1 ]b [L1 T-1 ]c
[M1 L1 T-2 ] = [M1 L-1 T-1 ]a [L1 ]b [L1 T-1 ]c
[M1 L1 T-2 ] = [ M a L- a + b + c T- a-c ]
On solving
a = 1, b = 1, c = 1
F = kηrv
F = 6πηrv
0
Terminal velocity :
The maximum constant velocity acquired by a body while falling through a viscous medium is called its terminal velocity.
W
U
F
As body falls various forces acting on body are
ρ
σ
i) Weight of the body acting vertically downwards
W = mg = 4/3 π r3 ρ.g
ii) Upward thrust equal to the weight of the liquid displaced
U = 4/3 π r3 σ.g
iii) Viscous force acting upward
F = 6π η r v
When the body attend terminal velocity
U + F = W
i.e.
When the body attend terminal velocity vt
4/3 π r3 σ.g + 6π η r vt = 4/3 π r3 ρ.g
6π η r vt = 4/3 π r3 (ρ – σ).g
vt =
r2 (ρ - σ) g
η
2
9
Note: if ρ < σ , the terminal velocity is -ve ex air bubble rises through fluid
0
Streamline flow :
When a liquid flows in such a way that each particle of the liquid passing a given point moves along the same path and has the same velocity as its predecessor, the flow is called streamline flow or steady flow.
Streamline :
A streamline may be defined as the path, the tangent to which at any point gives the direction of the flow of liquid at that point.
Properties of streamline flow:
Turbulent flow :
When the liquid velocity exceeds a certain limiting value, called critical velocity, the liquid flow becomes zig-zag. The path and velocity of liquid changes continuously, haphazardly. This flow is called turbulent flow. It is accompanied by random irregular, local circular currents called vertices.
0
Tube of flow :
Tube of flow is a bundle of streamlines having the same velocity of fluid element over any cross-section perpendicular to the direction of flow.
Laminar flow :
In a steady flow, liquid flows in the form of layer sliding past one another without getting mixed, called laminar flow.
Critical velocity :
The critical velocity of a liquid is that limiting value of its velocity of flow up to which the flow is streamlined and above which the flow becomes turbulent.
velocity is
vc α
η
ρ.D
vc =
Reη
ρ.D
where, Reynolds number.
Re =
ρ v D
η
Note :
0
Equation of continuity : a1v1 = a2v2
Bernoulli’s Principle:
It states that sum of pressure energy, kinetic energy and potential energy per unit volume of an incompressible, non-viscous fluid in a streamlined, irrotational flow remains constant along a streamline.
a1
A
B
a2
m = volume x density
m = area of cross-section x length x density
m = a1 v1 ∆t ρ = a2 v2 ∆t ρ
a1 v1 = a2 v2 …… (*)
change in K.E. of fluid
= K.E. at B – K.E. at A
= ½ m (v22 - v12)
= ½ a1 v1 ∆t ρ (v22 - v12)
change in P.E. of fluid
= P.E. at B – P.E. at A
= mg (h2- h1)
= a1 v1 ∆t ρ g (h2- h1)
Net work done (F.S) on the fluid
= work done on fluid at A – Work done on fluid at B
= P1 a1 x v1 ∆t – P2 a2 x v2 ∆t
= a1 v1 ∆t (P1– P2 )
According to law of conservation of energy
Net work done on fluid = Change in KE – change in PE
a1 v1∆t (P1–P2 )=½ a1v1∆t ρ(v22 - v12) - a1v1∆t ρ g(h2-h1)
Dividing both side by a1 v1 ∆t, we get
(P1–P2 ) = ½ ρ(v22 - v12) - ρ g (h2-h1)
P1 + ½ ρv12 + ρ g h1 = P2 + ½ ρv22 + ρ g h2
P + ½ ρv2 + ρ g h = constant
0
Speed of efflux (outflow): Torricelli’s Law
A1v1 = A2v2
v2 = A2/A1 .v1
Pa + ½ ρ v12 + ρgy1 = P + ρ g y2
½ ρ v12 = ρg( y2 – y1 ) + (P - Pa )
½ ρ v12 = ρgh+ (P - Pa )
v1 =
2(P-Pa)
ρ
√
2gh +
Note :
v1 =
2(P-Pa)
ρ
√
2) If tank is open to atmosphere is P = Pa, v1 = √2gh
This is speed of freely falling body known as Torricelli’s law
0
Applications of Bernoulli’s Principle :
it is a device used to measure the rate of flow of a liquid through a pipe.
1) Venturimeter :
It consists of a horizontal tube having wider opening of cross-section a1 and a narrower neck of cross-section a2. These two regions of the horizontal tube are connected to a manometer, connecting a liquid of density ρ’.
Let the liquid velocities be v1 and v2 at the wider and narrower end then according to principle of continuity.
A1v1 = A2v2
or
A1
A2
=
v2
v1
If P1 and P2 be the pressure at wider and narrower portion, ρ is density of fluid, then according to Bernoulli’s equation
P1 + ½ ρv12 = P2 + ½ ρv22
or
P1 – P2 = ½ ρ( v22 - v12 )
P1 – P2 = ½ ρ v12
v22
v12
(
)
– 1
P1 – P2 = ½ ρ v12
A12
A22
(
)
– 1
……. (1)
{ eqn (1)
P1 – P2 = ½ ρ v12
A12 – A22
A22
(
)
If h is the height difference in arms of manometer
P1 – P2 = h ρ’ g
h ρ’ g = ½ ρ v12
A12 – A22
A22
(
)
v1 =
√
2h ρ’ g
ρ
x
A12 – A22
A22
Volume of liquid flowing out per second
Q =A1v1 = A1A2
√
2h ρ’ g
ρ
(A12 – A22)
0
P1
P2
Container
Balloon
2) Automizer
3) Aerofoil :
Aerofoil is the name given to solid object shaped to provide an upward vertical force as it moves horizontally through the air
The difference in pressure provides an upward lift called dynamic lift.
0
4) Magnus effect :