60o
B
C
A
60 m
?
Q. A kite is flying at a height of 60m above the ground.
The string attached to the kite is temporarily tied to the ground.
The inclination of the string with the ground is 60o. Find the length of the string,
assuming that there is no slack in the string.
Sol.
AB represents the distance of the kite from ground.
AB = 60 m.
AC represents the length of the string.
∠ACB = 60o
In right angled ΔABC,
sin 60o =
=
AC =
AC =
The length of the string is 69.2 m
A
B
C
60m
60o
?
AB
AC
2
60
AC
120
120
3
Q. A kite is flying at a height of 60m above the ground.
The string attached to the kite is temporarily tied
to the ground. The inclination of the string with
the ground is 60o. Find the length of the string,
assuming that there is no slack in the string.
Opposite
side
Hypotenuse
Observe ∠C
sin 60o =
?
2
∴
∴
∴
For ∠ACB
Opposite side →
Hypotenuse →
AB
AC
Ratio of opposite side and Hypotenuse reminds us of _________
‘sin’
40
69.2 m
∴
Now, let us rationalise the denominator