Enter the Nanoworld
How do we observe, quantify, and draw conclusions about atoms if we cannot see them?
The Mole in Chemistry
What is a mole in chemistry?
Amedeo Avogadro (1776 - 1856)
studied quantities of gases and discovered that under the same pressure and temperature conditions, equal volumes of all gases contain the same number of molecules.
This is called Avogadro’s Hypothesis and is useful in helping chemists make predictions about ideal gases.
The mole allows us to measure atoms, even though we cannot see them
A MOLE EQUALS 3 THINGS:
(particles: atoms, molecules, formula units, etc.)
(STP is standard temperature and pressure)
One mole of any element or compound can be determined from its mass on the Periodic Table
The Mole and Avogadro’s Number
How Big is a Mole?
Mole Day
is celebrated on
October 23,
from
6:02 a.m. until 6:02 p.m.
2019 theme
2020 theme
2021 theme
Copy and complete the table below
using a periodic table.
Molar Mass and Number of Particles in a Mole
Element or Compound | Atomic Mass | Molar Mass | Number of Particles in one mole: |
Sodium (Na) | | | 6.022 x 1023 atoms |
Chlorine (Cl) | | | 6.022 x 1023 atoms |
Sodium Chloride (NaCl) | | | 6.022 x 1023 formula units |
Water (H2O) | | | 6.022 x 1023 molecules |
Molar Mass and Number of Particles in a Mole
Element or Compound | Atomic Mass | Molar Mass | Number of Particles in one mole: |
Sodium (Na) | 22.990 amu | 22.990 g/mol | 6.022 x 1023 atoms |
Chlorine (Cl) | 35.45 amu | 35.45 g/mol | 6.022 x 1023 atoms |
Sodium Chloride (NaCl) | 22.990 + 35.45 = 58.44 amu | 58.44 g/mol | 6.022 x 1023 formula units |
Water (H2O) | 2(1.008)
18.015 amu | 18.015 g/mol | 6.022 x 1023 molecules |
Finding Molar Mass of a Compound
To find the molar mass of H2O:
H: 2(1.008) = 2.016 g/mol
O: 1(15.999) = 15.999 g/mol
= 18.015 g/mol
Add
To find the molar mass of NaCl (sodium chloride)
or 58.44 g of NaCl = 1 mole of NaCl
Molar Mass (cont’d.)
Determine the molar mass of the below elements, molecules, or compounds:
Determine the molar mass of the below elements, molecules, or compounds:
Mole Conversions
Examples and Practice
Example 1: grams to moles
How many moles are in 24.022 g of carbon?
1 mol = 12.011 g C
24.022 g C x 1 mol C = 2.0000 mol C
12.011 g C
Example 2: moles to grams
How many grams is 2 moles of carbon?
2 mol C x 12.011 g C = 24.022 g C
1 mol C
Example 3: Liters to moles
How many moles are in 2.56 Liters?
(1 mol = 22.4 L of any gas @STP)
2.56 L x 1 mole = 0.114 moles
22.4 L
Example 4: moles to Liters
How many liters of helium gas are in 2.00 moles of He? (1 mol = 22.4 L of any gas @STP)
2.00 mol x 22.4 L = 44.8 L
1 mol
Example 5: atoms to moles
How many moles are in 7.84 x 1025 atoms?
1 mol = 6.022 x 1023 atoms (or molecules, or formula units)
7.84 x 1025 atoms x 1 mole =
6.022 X 1023 atoms
= 1.30 x 102 moles or 130. moles
Example 6: moles to atoms
How many atoms are in 4.00 moles?
1 mol = 6.022 x 1023 atoms (or molecules, or formula units)
4.00 moles x 6.022 X 1023 atoms =
1 mole
= 2.41 x 1024 atoms
When using the exponent button, the program puts in the power of ten.
2nd
EE
EE
EXP
x10x
Practice 1: Convert grams to moles
14.1g of Na = ? moles
1 mol Na = 22.990 g Na
Practice 1 Solution: grams to moles
14.1g of Na = ? moles
1 mol Na = 22.990 g Na
14.1 g Na 1 mol Na = 0.613 mol Na
22.990 g Na
Practice 2: moles to grams
How many grams in 1.5 moles sulfur?
( 1 mol S = 32.06g)
Solution to Practice 2:
How many grams in 1.5 moles sulfur?
( 1 mol S = 32.06g)
1.5 mol S x 32.06 g S = 48.09 g S
1 mol S
Practice 3: Liters to moles
How many moles are in 5.30 Liters?
(1 mol = 22.4 L of any gas @STP)
5.30 L x ? = ?
?
Practice 3 Solution: Liters to moles
How many moles are in 5.30 Liters?
(1 mol = 22.4 L of any gas @STP)
5.30 L x 1 mole = 0.237 moles
22.4 L
Practice 4: moles to Liters
How many liters of helium gas are in 1.40 moles of He? (1 mol = 22.4 L of any gas @STP)
Practice 4 Solution: moles to Liters
How many liters of helium gas are in 1.40 moles of He? (1 mol = 22.4 L of any gas @STP)
1.40 mol x 22.4 L = 31.4 L
1 mol
Practice 5: particles to moles
How many moles are in 6.38 x 1024 particles?
Practice 5 Solution: moles to particles
How many moles are in 6.38 x 1024 particles?
6.38 x 1024 particles x 1 mole =
6.022 X 1023 particles
= 10.6 moles
Example 6: L to particles
How many particles are in 12.6 Liters?
Conversion Factors: 1 mole = 22.4 L ; 1 mole = 6.022 x 1023 particles
Example 6: How many particles are in 12.6 Liters?
12.6 L x 1 mole
22.4 L
x 6.02 X 1023particles
1 mole
= 3.39 x 1023 particles
Example 7: grams to atoms �
How many atoms of sodium are found in 25.24 grams of sodium?
How many atoms of sodium are found in 25.24 grams of sodium?
1 mole of Na = 22.990 g of Na
1 mole of Na = 6.022 x 1023 atoms�
25.24 g Na ? ?
? ?
Example 7: grams to atoms
Example 7 Solution:
How many atoms of sodium are found in 25.24 grams of sodium?
22.990 g of Na = 1 mole of Na = 6.022 x 1023 atoms�
25.24 g Na 1 mol Na 6.022 x 1023 atoms Na
22.990 g Na 1 mol Na
= 6.611 x 1023 atoms Na
Practice 8:
Convert 7.5 x 1024 atoms Ca to moles
(1 mole Ca = 6.022 x 1023 atoms Ca)
Practice 8 Solution:
Convert 7.5 x 1024 atoms Ca to moles
7.5 x 1024 atoms Ca 1 mol Ca
6.022 x 1023 atoms Ca
= 12 moles Ca
Bell Work:
2. Convert 62.0 g Mg to atoms Mg
Bell Work:
1.5 x 1024 atoms Ca
2. Convert 62.0 g Mg to atoms Mg
Solving using molar mass:
Remember: