CHAPTER 9:
ELECTRICITY
CIRCUIT SYMBOLS page 61, Syllabus Book
Current Electricity
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Charge Carriers- positive or negative?
Electrolyte: a solution which conducts the current and contains both +ve & -ve ions. It allows current in batteries, electrolysis, body functions
Charge carriers: any charged particles which contribute to an electric current, such as p-type and n-type of semiconductor below
•The size of the electric current is given by the rate of flow of charge and is measured in units called amperes with symbol A.
•A current of 3 A means that 3C pass a point in the circuit every second. In 5 seconds, a total charge of 15C will have passed the point.
Q = It
I = Q/t
Charge & Coulomb
•From the definition of electric current, I,(recall?) we obtain,
Q = It
•Electric charge, Q flowing through a section of a circuit is the product of the electric current and the time that it flows.
e = 1.6 x 10-19 C (elementary charge)
ANS: B
ANS: B
From the diagram the following can be implied:
(e for electron)
For metal:
L
and
If current increases, the drift velocity must increase.
If the wire is thinner, the electron move more quickly for a given current.
Answer : C
Answer : B
Answer : B
Voltage
Potential difference between two points, is the energy given up (equal to work done) by unit charge as it moves from a point to another point in a circuit
Brightness of identical bulbs/ lamps depends on potential difference, V across it
e.m.f is defined as the total work done when unit charge goes round a complete circuit (charge gain electrical energy from power supply or a battery)
Answer : A
Electric Resistance
Resistance: the ratio of the potential difference to the current
To determine the resistance, need to measure both V and I.
Ohm’s Law
Ohm’s law states that the current I through a given conductor is directly proportional to the potential difference V between its end points.
Ohm’s law allows us to define resistance R and to write the following forms of the law:
Electric Power
Electric power P is the rate at which electric energy is expended, or work per unit of time.
V
q
V
Recall: Work done = qV
Substitute q = It , then:
P = VI
I
Unit: Watts = amps x volts
Calculating Power
Using Ohm’s law, we can find electric power from any two of the following parameters: current I, voltage V, and resistance R.
Power as energy transferred/ dissipated in unit time
Ohm’s law: V = IR
The brightness of a lamp depends on power its dissipated
A lamp dissipates more power produces more light and appears brighter
P=VI
A lamp becomes brighter when either the voltage across it or the current through it increases, because its power increases
P=I2R
If a greater current, I, flows through an identical lamp ( R constant), it dissipates more power and therefore glows more brightly.
P=V2/R
For identical lamps (R constant), a larger voltage across the lamp produces a larger power, so the lamp becomes brighter
RELATIONSHIP BETWEEN POWER AND BRIGHTNESS- WHY A LAMP GLOWS?
A lamp glows because electrical energy is converted into light and heat.
The rate at which energy is converted per second is called power.
Power =energy per second =rate of energy
So higher power → more energy per second → brighter light.