SERIES CIRCUITS
Unit 8: Electricity and Magnetism
SERIES CIRCUITS
SERIES CIRCUIT DIAGRAM
closed circuit
open circuit
+
-
+
-
gap = no current
CURRENT IN �SERIES CIRCUITS
RESISTORS IN �SERIES CIRCUITS
VOLTAGE CHANGES IN SERIES CIRCUITS
VT= 12V
IF YOU ADD RESISTORS TO A SERIES CIRCUIT
Voltage | decreases across each resistor (total voltage is the same) |
Current | remains the same |
SAMPLE PROBLEMS
for each problem, draw a circuit diagram
1. Three 20 Ω resistors are connected in series across a 120-V generator. �a. What is the total resistance of the circuit? �b. What is the current in the circuit?
Givens
R1 = R2 = R3 = 20 Ω
Rtotal = ?
V = 120 V
I = ?
a. Rtotal = R1 + R2 + R3
Rtotal = 20 + 20 + 20
Rtotal = 60 Ω
b. I = V/R
I = 120/60
I = 2 A
R1 = 20Ω
R2 = 20Ω
R3 = 20Ω
120 V
2. A 10 Ω, 15 Ω, and 20 Ω resistor are connected in a series across a 90-V battery. �a. What is the total resistance of the circuit? �b. What is the current in the circuit
Givens
R1 = 10 Ω
R2 = 15 Ω
R3 = 20 Ω
V = 90 V
I = ?
a. Rtotal = R1 + R2 + R3
Rtotal = 10 + 15 + 20
Rtotal = 45 Ω
b. I = V/R
I = 90/45
I = 2 A
90 V
10 Ω
15 Ω
20 Ω
2. A 10 Ω, 15 Ω, and 20 Ω resistor are connected in a series across a 90-V battery. �c. What is the voltage drop across each resistor?
Givens
R1 = 10 Ω
R2 = 15 Ω
R3 = 20 Ω
V = 90 V
I = ?
**note: when you calculate voltage drop, you use the value of resistance at each resistor, BUT current is the same throughout
R1 = 10 Ω
I = 2 A
V = ?
I = V/R
2 = V/10
V = 20 V
90 V
10 Ω
15 Ω
20 Ω
R2 = 15 Ω
I = 2 A
V = ?
I = V/R
2 = V/15
V = 30 V
R3 = 20 Ω
I = 2 A
V = ?
I = V/R
2 = V/20
V = 40 V
20 V + 30 V + 40 V = 90 V
8.2 LESSON CHECK