Lesson 1-3 Compare and Order Real Numbers
Area of Quadrilaterals = s x s
Area of Rug 1 = 7 x 7 = 49
1
2
3
Area of Rug 3 = 6 x 8.5 = 51
Area of Circles = π x r2
β
Area of Rug 2 = 3.14 x 42 = 50.27
Irrational Number, not a perfect square. We need to rationalize it by making it a decimal
9
16
3
4
β9
β16
3
4
β9
β16
β12
π
STEP 1: THEY MUST ALL BE IN THE SAME NUMBER FORMAT which will be DECIMALS
π
Find the value of 2
π
= 3.14
π
So 3.14 x 3.14 =
9.8596
=9.9
β
π
9.5
No change
9.5
= 9.6
π
β81
β100
9
10
9.8 x 9.8
= 96.04
9.7 x 9.7
= 94.09
π
9.5
9.8
9.6
9.9
9.7
9
10
π
STEP 1: THEY MUST ALL BE IN THE SAME NUMBER FORMAT which will be DECIMALS
2.25
3.7
-2.5
-4
β11
β9 <
< β16
3
4
3.2 x 3.2
= 10.24
3.3 x 3.3
= 10.89
2.25
3.7
-2.5
-4
3.3
-5
5
0
36 < 39 <49
β
6 < 39 < 7
β
Closest to 36 so whole number = 7
5.7145β¦β¦ 25 < 29 < 36
β
Rounds to 5.7 5 < 29 < 6
β
Use approximations to get rational number for square root 29...guessβ¦..
5.4 x 5.4 = 29.16 = too high so 5.3
β
Therefore 5.7145β¦ > square root 29
β
16 < 18 < 25
β
4 < 18 < 5
β
Use approximation to get the rational numberβ¦.so guessβ¦.
4.2 x 4.2 = 17.64 just right
4.3 x 4.3 = 18.49 too high
5.2 No change
-5.6 repeating...rounds to -5.7
3 9/10 changes to 3.9
β
Then square root 21 is between 16 and 25. So approximate 4.6 x 4.6 = 21.16 is close
4.5 x 4.5 = 20.25 which is further way. So 4.6 it is
Negative Square Root
-β57 what this really means is -1 x β57
-β49 < -β57 < -β64
7 < β57 < 8 square root 57 is 8 from 49 and 7 from 64 so letβs approximate a decimal that is halfway between 7 and 8 soβ¦
7.5 x 7.5 = 56.26 a little low (0.74 away from 57)
7.6 x 7.6 = 57.76 a little high (0.76 over 57)
Since 7.52 is closer the square root of -β57 is -7.5