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Lesson 1-3 Compare and Order Real Numbers

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Area of Quadrilaterals = s x s

Area of Rug 1 = 7 x 7 = 49

1

2

3

Area of Rug 3 = 6 x 8.5 = 51

Area of Circles = πœ‹ x r2

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Area of Rug 2 = 3.14 x 42 = 50.27

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Irrational Number, not a perfect square. We need to rationalize it by making it a decimal

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9

16

3

4

√9

√16

3

4

√9

√16

√12

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πœ‹

STEP 1: THEY MUST ALL BE IN THE SAME NUMBER FORMAT which will be DECIMALS

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πœ‹

Find the value of 2

πœ‹

= 3.14

πœ‹

So 3.14 x 3.14 =

9.8596

=9.9

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πœ‹

9.5

No change

9.5

= 9.6

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πœ‹

√81

√100

9

10

9.8 x 9.8

= 96.04

9.7 x 9.7

= 94.09

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πœ‹

9.5

9.8

9.6

9.9

9.7

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9

10

πœ‹

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STEP 1: THEY MUST ALL BE IN THE SAME NUMBER FORMAT which will be DECIMALS

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2.25

3.7

-2.5

-4

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√11

√9 <

< √16

3

4

3.2 x 3.2

= 10.24

3.3 x 3.3

= 10.89

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2.25

3.7

-2.5

-4

3.3

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-5

5

0

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36 < 39 <49

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6 < 39 < 7

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Closest to 36 so whole number = 7

5.7145…… 25 < 29 < 36

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Rounds to 5.7 5 < 29 < 6

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Use approximations to get rational number for square root 29...guess…..

5.4 x 5.4 = 29.16 = too high so 5.3

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Therefore 5.7145… > square root 29

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16 < 18 < 25

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4 < 18 < 5

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Use approximation to get the rational number….so guess….

4.2 x 4.2 = 17.64 just right

4.3 x 4.3 = 18.49 too high

5.2 No change

-5.6 repeating...rounds to -5.7

3 9/10 changes to 3.9

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Then square root 21 is between 16 and 25. So approximate 4.6 x 4.6 = 21.16 is close

4.5 x 4.5 = 20.25 which is further way. So 4.6 it is

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Negative Square Root

-√57 what this really means is -1 x √57

-√49 < -√57 < -√64

7 < √57 < 8 square root 57 is 8 from 49 and 7 from 64 so let’s approximate a decimal that is halfway between 7 and 8 so…

7.5 x 7.5 = 56.26 a little low (0.74 away from 57)

7.6 x 7.6 = 57.76 a little high (0.76 over 57)

Since 7.52 is closer the square root of -√57 is -7.5