Targeting Grade C
Unit 1
Algebra 1
GCSE Mathematics
TOP 1: Review 1 - collecting like terms
Practice 1: Multiplying a bracket by a whole number or letter
Practice 2: Expand the brackets and simplify the expression by collecting the like terms
TAIL 1
Practice 3: Multiplying and dividing indices in algebra
TOP 2: Review 2 – substituting numbers for letters
TAIL 2
Can you:
Try a test
Try a test
If not you need
TOP 1: Simplify
(i) 3g + 5g
(ii) 3x + y - x + 2y
(2)
(b) 4a + 9b – 3a – 5b
(1)
(c) 3p + q – 2p – 2q
(2)
(1)
(Total 7 marks)
Lesson
8g
2x + 3y
a + 4b
p - q
-2v -w
4x² - x
Are you ready for the answers ?
Practice 1: Expand the brackets:
(a) (i) 7(n – 3)
(ii) 4(2x – 3)
(iii) p(q – 2p)
Multiply out: (3)
(1)
(c) x(2x +y)
(2)
Lesson
7n - 21
8x -12
pq – 2p²
10y - 15
2x² + xy
Are you ready for the answers ?
Practice 2: Expand and simplify:
(i) 4(x + 5) + 3(x – 7)
(2)
(ii) 5(3p + 2) – 2(5p – 3)
(2)
(iii) (t + 4)(t – 2)
(2)
(iv) (x + 3y)(x + 2y)
(2)
Lesson
4x + 9 + 3x -21 = 7x - 12
15p + 10 - 10p + 6 = 5p +16
t² - 2t + 4t -8 = t² + 2t -8
x² + 2xy + 3xy + 6y² = x² + 5xy + 6y²
Are you ready for the answers ?
e + f + e +2f
Answers
1
2
3
4
5
6
7
8
9
10
2x² + 2x + 3x² - x
2(a + b)
5(2d + 2e)
x(x + y)
a(3a + 2b)
3(x + y) + 2(x – 2y)
5(3x + 2) – 3(4x – 3)
(x + 3)(x - 2)
(2a + b)(3a – 2b)
TAIL 1
Are you ready for the answers ?
e + f + e +2f
1
2
3
4
5
6
7
8
9
10
2x² + 2x + 3x² - x
2(a + b)
5(2d + 2e)
x(x + y)
a(3a + 2b)
3(x + y) + 2(x – 2y)
5(3x + 2) – 3(4x – 3)
(x + 3)(x - 2)
(2a + b)(3a – 2b)
2e + 3f
5x² + x
2a + 2b
10d + 10e
x² + xy
3a² + 2ab
5x - y
3x + 19
x² + x - 6
6a² - ab –2b²
TAIL 1
Lesson
Can you remember the rules of indices (or powers)?When MULTIPLYING, you ADD the powers. e.g. 3¹ X 3² = 3³When DIVIDING, you SUBTRACT the powers. e.g. 4³ ÷ 4² = 4¹.. and for few more click mouse…
Anything to the POWER 1 is just ITSELF. e.g. 5¹ = 5 x¹ = xAnything to the POWER 0 is just 1. e.g. 6º = 1 xº = 1
When RAISING one power to another, you MULTIPLY the powers. e.g. (3²)³ = 36 (45)² = 4¹0
Now try some questions
Can you Simplifying indices?
Write down your solutions to:
1. k³ ÷ k²
2. p² × p3
x4
x²
(7)
Lesson
k¹
p5
3p²
x¹¹
x²
a¹º
x³
Are you ready for the answers ?
By using substitution answer the following questions:
(i) Work out the value of 2a + ay when a = 5 and y = –3
(2)
(ii) Work out the value of 5t² - 7 when t=4
(iv) Work out the value of D when: (4)
D = ut + 2kt
If u = 5
t = 1.2k = –2
(3)
Lesson
-5
73
-14
1.2
Are you ready for the answers ?
TAIL 2
2p + 3q
2y²
3c + 4d
8pq
2x³
Some more questions
Are you ready for the answers ?
Can you work out the answers to these?1. 3¹ 2. 8º 3. (2³)4 4. (4² x 4¹) ÷ (2³ x 2²)
Lesson
3
1
2¹²
2
Are you ready for the answers ?