Bombardier� Challenger 650
Static Stability Analysis
Technical Report
Stability & Control
Group - 3
Ganjare Aavishkar (22AE30010)
Weight & Center of Gravity
Balance points define aircraft stability and control characteristics.
Empty C.G.
10.10
m
Operating Empty: 12,315 kg
MTOW C.G.
10.79
m
MTOW: 21,315 kg
0.69
m
Aft Shift
Ganjare Aavishkar (22AE30010)
MAC & Static Margin
Mean Aerodynamic Chord
Geometric reference for aerodynamic balancing
MAC (c̄)
2.595m
meters
Aerodynamic Center
Wing AC location from aircraft nose. It’s the point on the airfoil about which the aerodynamic moment is independent of AoA.
X_ac
11.5m
meters
Static Margin
At MTOW
27.3%
percent
Natural Longitudinal Stability
Positive static margin ensures the aircraft naturally returns to equilibrium after disturbances
Priyangshu (22AE10048)
Static Margin is a measure of natural longitudinal stability,
Longitudinal Static Stability (Cmα)
Quantifies the aircraft's natural tendency to pitch down and recover when disturbed.
Wing contribution provides baseline, enhanced by T-tail configuration with high tail volume coefficient
Lift Curve Slope (CLα)
from airfoil data
0.1
per degree
Static Margin
CG to AC distance
27
percent
Wing Contribution
baseline estimate
-0.027
per degree
Total Aircraft Cmα
with T-tail enhancement
-0.02 ~ -0.04
per degree
Phani Surya (22AE30006)
Pitching Moment Calculation
Equilibrium Condition: ΣCm = 0
Wing
Moment Arm
11.5 - 10.79 = 0.71 m
Normalized (Static Margin)
0.71 / 2.595 = 0.273
Lift Component
-0.48 × 0.273 = -0.131
Airfoil Component
Cm,ac ≈ 0 (negligible)
Tail
Tail Volume Coefficient
VHT = 0.735
Tail Lift Coefficient
CL,tail ≈ -0.12
Incidence Setting
-2° to -3° (Raymer)
Restoring Moment
-0.735 × (-0.12) = +0.088
Fuselage
Equilibrium Equation
0 = -0.131 + 0.088 + Cm,fuselage
Solve for Cm,fuselage
Cm,f = 0.131 - 0.088
Moment Equation
Cm,f = 0.043
Phani Surya (22AE30006)
Trim Angle Calculation
Cruise Condition
Mach 0.80 @ 37,000 ft
Cruise Weight
199864 N
Pressure
21.7 kPa
Density
0.364 Kg/m3
Required CL to sustain Cruise Flight
Lift Curve Equation
Symmetrical Airfoils
NACA 0011-64 & 0010-64
CL0 = 0
Simplified Equation
α = CL / CLα
Trim Angle Derivation
CLα ≈ 0.1 per degree
α = 0.45 / 0.1
4.5
°
Dheeraj (22AE30009)