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Unit I: Matter & Change

Unit 1, Notes 2: Laws of Matter

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I can ...

  • Identify pure substances.
  • Identify mixtures.
  • Identify the parts of a compound.
  • Solve problems based upon the Law of Definite proportions.
  • Solve problems based upon the Law of Conservation of Matter

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B. Pure Substance Review

    • The same properties throughout = homogeneous
    • Different properties = heterogeneous

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B. Pure Substances

  • Because they have the same CHEMICAL FORMULA throughout.
    • A chemical formula (H2O) contains:
      • symbols of the elements present
      • subscripts identifying the ratio (or proportion) those elements are combined in.

H2O

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B. Pure Substances

  • A pure substance
    • Can be made up of a single element: He
    • Can be a compound which contains two or more elements: H2O

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B. Pure Substances

  • Easy identification:
    • The formula of an ELEMENT only contains one capital letter
    • The formula for a COMPOUND can contain several capital letters (one for each element).

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B. Pure Substances

  • It is NOT a pure substance if
    • Different parts of the sample have different physical or chemical properties (e.g. sand, granite, fizzy soda pop, a book, a frog)
    • Different parts of the sample have different chemical formulas

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Pure Substances (a) vs. Mixtures (b)

    • Table salt
    • Granite
    • Gold
    • Pond water
    • Sand
    • Distilled water
    • Calcium
    • Blood

  • Pure (compound)
  • Mixture
  • Pure (element)
  • Mixture
  • Mixture
  • Pure (compound)
  • Pure (element)
  • Mixture

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Formulas

    • Elements
      • Are usually easy to identify from their names
      • if the name matches a square on the periodic table, it is an element.
      • If there is not a periodic table square for it, it is probably not an element.

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Formulas

  • Some elements never appear in nature as individual atoms.
      • Seven of those are called the “diatomic” elements because they always appear two atoms at a time in their elemental form.
      • (H2, N2, O2, F2, Cl2, Br2, I2)

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Formulas

    • Carbon is even sneakier. There are three common forms of elemental carbon, and each has a different name even though they all share the same formula.
    • (This is due to different bond structures, which we’ll talk about later in the year.)

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Formulas

    • Carbon is even sneakier. There are three common forms of elemental carbon, and each has a different name.
          • Cx = graphite
          • Cx = coal
          • Cx = diamond

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Formulas

  • SUBSCRIPTS
    • Are the small numbers at the bottom of a formula.
      • H2
      • NO3
      • P2O5
      • Ca(ClO3)2

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Formulas

  • SUBSCRIPTS
    • Indicate the number of atoms of each element
    • Or the proportion between two elements.
      • H2
      • NO3

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Formulas

  • SUBSCRIPTS
    • Indicate the number of atoms of each element
    • Or the proportion between two elements.
      • P2O5 means:

2 phosphorus : 5 oxygen

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Formulas

  • SUBSCRIPTS
    • Indicate the number of atoms of each element
    • Or the proportion between two elements.
      • Ca(ClO3)2 means:

1 calcium : 2 chlorine

1 chlorine : 3 oxygen

1 calcium : 6 oxygen

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Formulas

  • C6H12O6 means:
    • 1 C = __ H
    • 1 C = __ O
    • 1 O = __ H

2

1

2

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Formulas

  • Al(NO3)3 means:

    • 1 Al = __ N
    • 1 N = __ O
    • 1 Al = __ O

3

3

9

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Laws of Matter

    • The Law of Definite Proportions states that a compound always contains elements in the same proportions by mass.

H2O

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The Law of Definite Proportions means:

    • Every sample of water from everywhere on the planet (or some other planet, for that matter) will have 2 hydrogens with 1 oxygen.
    • That proportion DEFINES water.
    • The 2:1 PROPORTION of H to O is what makes it water.

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The Law of Definite Proportions:

Ratio problems!

  • If 4.0 g of element A combine with 10. g of element B
    • Then 12 g of element A should combine with ____ g of element B.

4 g A = 10. g B

12 g A = ___g B

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The Law of Definite Proportions:

Ratio problems!

  • If 4.0 g of element A combine with 10. g of element B
    • Then 12 g of element A should combine with ____ g of element B.

4 g A 10. g B

12 g A X g B

=

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The Law of Definite Proportions:

Ratio problems!

  • If 4.0 g of element A combine with 10. g of element B
    • Then 12 g of element A should combine with ____ g of element B.

4 10.

12 X

=

4 X = 12(10)

X = 30

30

Cross multiply!

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The Law of Definite Proportions:

Ratio problems!

  • If 50. g of element A combine with 15 g of element B
    • Then 160. g of element A should combine with ____ g of element B.

50. g A = 15 g B

160 g A = ___g B

50 X = 160(15)

X = 48

48

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Laws of Matter: Chemical Formulas

      • If you change the ratio, you’ll get a different compound with different properties.
        • H2O is water.
        • H2O2 is hydrogen peroxide.
        • They are NOT the same!!

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Multiple Proportions:

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Laws of Matter: Chemical Formulas

    • The Law of Multiple Proportions:
    • If two elements can combine in more than one small, whole-number ratio (proportion), different compounds with different properties will be produced.

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Laws of Matter: Chemical Formulas

    • The Law of Multiple Proportions:
    • If two elements can combine in more than one small, whole-number ratio (proportion), different compounds with different properties will be produced.

1

1

1

3

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Conservation of Matter

    • The Law of Conservation of Matter:
      • Matter (mass) is not created or destroyed in a chemical reaction.

You always end a reaction having all the same atoms you started with.

(They just rearrange.)

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Conservation of Matter

    • The Law of Conservation of Matter:

Balanced equation:

3 A1B1 → 3 A + 3 B

You always end a reaction having all the same atoms you started with.

(They just rearrange.)

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Conservation of Matter

    • The Law of Conservation of Matter:

The number of ATOMS of each element is the same before and after.

The total number of GRAMS is the same before and after.)

+

+

AB2 + C → ABC + B

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Conservation of Matter

    • The Law of Conservation of Matter:

The number of ATOMS of each element is the same before and after.

__Na + __Cl2 → __NaCl

2

2

1

__Al + __O2 → __Al2O3

3

2

4

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Conservation of Matter

  • If 500. grams of NaN3 decomposes to form 323.20 grams of N2, how much Na is produced?

Reactants:

500. g

Product 1:

323.20 g

Product 2:

-

176.80 g

177 g

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I can ...

  • Identify pure substances.
  • Identify mixtures.
  • Identify the parts of a compound.
  • Solve problems based upon the Law of Definite proportions.
  • Solve problems based upon the Law of Conservation of Matter

LPHSChem.com: Wentz after Johannesson