INTRO TO MOTION
PART 1
VECTORS, SCALARS, AND DISTANCE VS. DISPLACEMENT
Vectors and Scalars
east
+
-
+
-
north
west
south
Nicole Ferreira 07
origin
vector
5 meters
left
Distance vs. Displacement
Distance is the total length covered during a trip. (Scalar)
d = AB + BC + CD + DE + EF
d = 6 + 2 + 3 + 1 + 1
d = 13 meters
Distance vs. Displacement
Displacement is a measure of how far and in what direction you are from a starting point. (Vector)
Note: Δ is the Greek letter Delta, meaning “a change in”
Distance vs Displacement
100 m
200 m
0 m
When an object moves in a straight line,
distance = displacement
A football player runs 35 meters east before realizing he is running toward the wrong goal. He immediately changes direction and runs 23 meters west before getting tackled.
a) What distance did the athlete travel during the play?
b) What is athlete’s displacement at the end of the play?
35 m
23 m
distance = 35 m + 23 m
distance = 58 m
∆x = xf – xi
xi = 0
xf = 35 – 23
xf = 12 m
∆x = 12 – 0
∆x = 12m
Review
PART 2
SPEED, VELOCITY, AND AVERAGE VELOCITY VS. CONSTANT VELOCITY
Speed
Velocity
60 m/s = speed
60 m/s northwest = velocity
Average Velocity
v = velocity 🡪 unit is m/s
∆x (displacement) = xf – xi 🡪 unit is m
t = time 🡪 unit is s
Sample Problems
1. James has an electronic Thomas the Tank Engine. Thomas travels a distance of 75 cm in 15 seconds.
What is Thomas’ speed during the time interval?
Use the GUESS Method:
Givens Unknown Equation Substitution Solution
d = 75 cm
= 0.75 m
t = 15 s
G
U
s = ?
E
S
S
s = 0.75
15
s = d
t
s = 0.05 m/s
2. A car travels at a rate of 15 m/s for 3 s. What is the displacement of the car?
Use the GUESS Method:
Givens Unknown Equation Substitution Solution
v = 15 m/s
t = 3 s
G
U
∆x = ?
E
S
S
15 = ∆x
3
v = ∆x
t
∆x = 45 m
3. Emily’s dog, Clifford, escapes from the yard and runs to the neighbor’s house covering 82 m in 20 s. He then realizes, he has not been fed and walks halfway back in 38 s.
a) What is Clifford’s average speed during his entire trip?
d = 82 + 41 = 123m
t = 20 + 38 = 58s
G
U
s = ?
E
S
S
s = 123m
58s
s = d
t
s = 2.12 m/s
3. Emily’s dog, Clifford, escapes from the yard and runs to the neighbor’s house covering 82 m in 20 s. She then realizes, she has not been fed and walks halfway back in 38 s.
b) What is Clifford’s average velocity during her entire trip?
xi = 0
xf = 82 – 41 = 41m
t = 58 s
G
U
v = ?
E
S
S
v = (41 – 0) = 41
58 58
v = ∆x = xf - xi
t t
v = 0.71 m/s
4. You ride your bike 1 m at 3 m/s and then another 1 m at 5m/s. Is your average velocity for the total 2m trip greater than, less than, or equal to 4 m/s?
Support your answer through a calculation.
vav = 3.8 m/s
vav < 4