Sheet metal bending
the inner portion of the bend compresses
while the outer portion expands
1. K – Factor,
the neutral axis to the material thickness.
K = t/T
K = 2.5 / 5
K = 0.5
L1
L2
OAL
Radius | Soft / Aluminum | Medium / Steel | Hard / Stainless Steel |
Air Bending |
|
|
|
0 - MT | 0.33 | 0.38 | 0.4 |
Mt. - 3* MT | 0.4 | 0.43 | 0.45 |
3*MT - >3* MT | 0.5 | 0.5 | 0.5 |
Bottom Bending |
|
|
|
0 - MT | 0.42 | 0.44 | 0.46 |
MT - 3*MT. | 0.46 | 0.47 | 0.48 |
3*T - >3*T | 0.5 | 0.5 | 0.5 |
Coining |
|
|
|
0 - MT | 0.38 | 0.41 | 0.44 |
Mt. - 3*T | 0.44 | 0.46 | 0.47 |
3*MT - >3*MT | 0.5 | 0.5 | 0.5 |
determine the angle of the bend in the
metal sheet.
by how far down vertically the punch presses
into the die.
sheet metal is pressed against a bottom die
featuring a V shape
K – Factor Chart
2. Neutral axis, Neutral axis offset
Example : Aluminum + 10R + Air bending
K = 0.4 & t = ?
K = t/T
0.4 = t / 5
t = 0.4 X 5
t = 2.0
Neutral Axis = 2.5mm
Neutral Axis offset = 2.0mm
The location of the neutral axis varies and is based on the material’s physical properties
and its thickness.
3. Bend allowance
L1
L2
OAL = L1+BA+L2
OAL = 25 + 19.63+ 25 = 69.63 mm
BA
Bend allowance is defined as the material required to add to the
overall length of the sheet metal in order for it to get cut in the right size
OAL
Bend allowance
= Angle X (ᴫ /180) X (Radius + K factor X MT)
= 90 X (ᴫ/180) X (10 + 0.5 X 5)
= 90 X 0.0174 X 12.5
= 19.63 mm
“BA is the length of the arc on the neutral axis”
arrive at the proper length in the flat pattern.
Bend deduction
= (2 × Outside setback) - Bend allowance
= (2 x 15) – 19.63
= 30 – 19.63
= 10.37 mm
4. Bend Deduction
L1
L2
OAL
BD