Lecture 11
Circuit theorem
Circuit theorem
Circuit theorem: Superposition theorem�
In a linear circuit, the current or voltage of any branch can be regarded as the algebraic sum of the current or voltage generated on the branch when each independent power source in the circuit acts on the circuit alone.
Proof:
Based on node voltage method, the KCL equation at node 1 is
(G2 + G3)*un1 = G2*us2 + G3*us3 + is1 (1)
us3
+
-
i2
1
G1
G2
G3
us2
+
-
is1
i3
This branch is equivalent to is1 only.
un1 = us2*G2/(G2 + G3) + us3*G3 /(G2 + G3) + is1/(G2 + G3)
un1 = is1*a1 + us2*a2 + us3*a3
or un1 = un1(1) + un1(2) + un1(3)
Circuit theorem: Superposition theorem
us3
+
-
i2
1
G1
G2
G3
us2
+
-
is1
i3
This branch is equivalent to is1 only.
The branch current can be
i2 = (un1 -us2)*G2
=-(G2*G3)*us2 /(G2+G3) + (G2*G3)*us3/(G2+G3)
+ G2*is1/(G2+ G3)
= is1*b1 + us2*b2 + us3*b3
= i2(1) + i2(2) + i2(3)
i3 = (un1 –us3)*G3
=(G2*G3)*us2 /(G2+G3) + (-G2*G3)*us3/(G2+G3)
+ G3*is1/(G2+ G3)
= i3(1) + i3(2) + i3(3)
Note:
Circuit theorem: Superposition theorem
us3
+
-
i2
G1
G2
G3
us2
+
-
is1
i3
i2
G1
G2
G3
is1
i3
=
+
i2
G2
G3
us2
+
-
i3
+
i2
G2
G3
us3
+
-
i3
Circuit theorem: Superposition theorem
Note:
Circuit theorem: Superposition theorem
2A
70V
+
-
4Ω
10Ω
2Ω
5Ω
i
Example: to solve the current i of the voltage source and its power
70V
+
-
4Ω
10Ω
2Ω
5Ω
i(1)
2A
4Ω
10Ω
2Ω
5Ω
i(2)
=
+
=
70V
+
-
14Ω
7Ω
i
+
2A
4Ω
10Ω
2Ω
5Ω
bridge circuit
Circuit theorem: Superposition theorem
Wheatstone bridge circuit
If RA*RD = RB*RC 🡪 vbc=0 🡪 no current between b and c
Circuit theorem: Superposition theorem
Example: to solve the current i and voltage u (This example is used as an assignment as well)
u
+
-
2Ω
10V
+
-
5A
i
1Ω
2i
+
-
u(1)
+
-
2Ω
10V
+
-
i(1)
1Ω
2i(1)
-
u(2)
2Ω
+
-
5A
i(2)
1Ω
2i(2)
+
-
+
+
=
KVL
Circuit theorem: Superposition theorem
Homogeneity principle:
In a linear circuit, if all excitation (independent power supply) increases or decreases by the same factor, the response (current or voltage) in the circuit also increases or decreases by the same factor.
us3
+
-
i2
1
G1
G2
G3
us2
+
-
is1
i3
un1 = is1*a1 + us2*a2 + us3*a3
or un1 = un1(1) + un1(2) + un1(3)
k*un1 = (k*is1)*a1 + (k*us2)*a2 + (k*us3)*a3
Circuit theorem: Superposition theorem
1Ω
1Ω
+
-
Assignment: Applying the homogeneity principle to solve the current i
1Ω
1Ω
1Ω
1Ω
2Ω
51V
i
Circuit theorem: Superposition theorem
i
is
us
+
-
passive linear network
no power source present in the black box
If us=1V, is=1A, we have i=2A
If us=-1V, is=2A, we have i=1A
What if us=-3V, is=5A, i=?
Assignment
Circuit theorem: Superposition theorem
6Ω
6V
3Ω
1Ω
3A
2A
12V
+
+
-
-
Assignment: to solve the voltage u
+
-
u?