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Logical Assignment Operators

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For Stage 3

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In a nutshell

Input

Output

a ||= b

a || (a = b)

a &&= b

a && (a = b)

a ??= b

a ?? (a = b)

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Decided on Short Circuiting

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  • Common cases are unobservable anyways
  • Don't need to worry about destructive Setters
  • Precedence from Ruby, CoffeeScript, and C#

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Checklist

  • ✅ Spec Text
  • ✅ Reviewers
    • ✅ Kevin Gibbons (#15)
    • ✅ Daniel Rosenwasser (#20)
  • ✅ Editors (#17)
    • ✅ Kevin Gibbons
    • ✅ Shu-yu Guo
    • ✅ Jordan Harband
    • ✅ Michael Ficarra
  • ✅ Test262 (#2559, #2560)

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Syntax is very simple

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Semantics are very simple

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Semantics are very simple

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Semantics are very simple

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Stage 3?