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Mathematics –Class XII��Unit IV-Vector & 3D

Chapter 11 -Three Dimensional Geometry

Sub Topic-Other Various Form of Equation of Plane

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  • Plane passing through the intersection of two planes.
  • Intercept form of a plane.
  • Condition for co planarity of two lines.
  • Assignment

Outline:�

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Plane Passing through the intersection of two planes

  • Let r . n1 = d1 ------( 1 ), r . n2 = d2 ----(2)

be the equations of two given planes.

  • Two Planes intersect in a line. Hence the points on the line are also satisfies the plane
  • Let a be the position vector of any point on this line. Then point A has to satisfy both the planes.
  • Therefore a . n1 = d1 and a .n2 = d2, for some parameter λ, the equation of the required plane is
  • (a . n1 – d1) + λ ( a . n2 – d2) = 0

which is in the vector form.�

BACK

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INTERCEPT FORM OF A PLANE

  • Let the general form of equation of the plane be�Ax + By + Cz = D ( D ≠ 0 ) ------ ( 1 )
  • Consider the intercepts on x – axis, y – axis and z – axis are a, b and c respectively by the plane (1), then plane passes through the points ( a, 0, 0), (0, b, 0) and (0, 0, c)
  • Hence Aa + D = 0 ⇒ A = -D/a
  • Similarly Bb + D = 0 ⇒ B = -D/b

and Cc + D = 0 ⇒ C = -D/c

  • Substituting these values in the equation (1), Then the equation of the plane be

x + y + z = 1

a b c

BACK

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Condition for Co planarity of two lines

  • Let the equations of two lines be

r = a1 + λb1 ---- ( 1 ) , where a1 is the position vector of a point A.

  • r = a2 + μb2 -- ( 2), where a2 is the position vector of a point B.
  • Then b1 x b2 is perpendicular to both the lines (1) and (2).
  • That is b1 x b2 is parallel to the normal of the plane which contains lines (1) and (2)

CONTINUE

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Continue ---

  • Since the require plane contains the two given lines, plane is also passing through both the points A and B.
  • Hence vectors AB, b1 and b2 are coplanar vectors.
  • Therefore [ AB , b1 , b2 ] = 0
  • ⇒ ( a2 – a1) . b1 x b2 = 0

BACK

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Condition for Co planarity of two lines in Cartesian Form

  • Let x – x1 = y – y1 = z – z1 ------ ( 1 )a1 b1 c1and x – x2 = y – y2 = z – z2 ------ ( 2 )

a2 b2 c2

are the equations of two lines, then condition for co planarity of two lines is

( x2 – x1) (y2 – y1) (z2 – z1)

a1 b1 c1 = 0

a2 b2 c2

BACK

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Q1.Find the equation of the plane passing through the intersection of planes �x + y + z – 6 = 0 , 2x + 3y + 4z + 5 = 0 and passing through the point ( 1, 1, 1)

ASSIGNMENTS