Solubility and Double Replacement Reactions
Vocabulary
“Two Couples” by Zule - Brazil
AP Topics
Topic 4.7 Types of Chemical Reactions
What happens in a double replacement reaction?
AB + CD 🡪 AD + CB
In aqueous solution, ions from two different ionic compounds switch places.
+
🡪
+
What happens in a double replacement reaction?
Dissociation
Ionic compounds dissolve by dissociation where ions are pulled apart due to their attraction to the opposite poles of water molecules.
Watch
Why do some of the substances dissolved in water conduct electricity and some do not?
Dissociation
When an ionic compound like sodium chloride dissolves in water, the ions dissociate. Take a look:
The ions are more attracted to the water molecules than they are to each other.
Dissociation
Not all ionic compounds dissociate
Cu2+
Cu2+
Cu2+
NO3-
NO3-
NO3-
NO3-
NO3-
NO3-
Pb2+
Pb2+
Pb2+
I-
I-
I-
I-
I-
I-
Cu(NO3)2
PbI2
How Can You Tell?��Solubility Rules!
Insoluble
= does not dissolve in water
= solid
Soluble� = dissolves in water
= aqueous
Cu2+
Cu2+
Cu2+
NO3-
NO3-
NO3-
NO3-
NO3-
NO3-
Pb2+
Pb2+
Pb2+
I-
I-
I-
I-
I-
I-
Cu(NO3)2
PbI2
Cu2+
Cu2+
Cu2+
NO3-
NO3-
NO3-
NO3-
NO3-
NO3-
Pb2+
Pb2+
Pb2+
I-
I-
I-
I-
I-
I-
Cu(NO3)2
PbI2
Solubility...what do you need to know?
Equation Practice
Aqueous potassium iodide reacts with aqueous lead(II) nitrate.
Step 1
Write the formulas for each of the reactants.
KI (aq)
+
Pb(NO3)2 (aq)
Aqueous potassium iodide reacts with aqueous lead(II) nitrate.
Step 2
KI (aq)
+
Pb(NO3)2 (aq)
→
PbI2
+
KNO3
Aqueous potassium iodide reacts with aqueous lead(II) nitrate.
Reminder
KI (aq)
+
Pb(NO3)2 (aq)
→
PbI2
+
KNO3
2+ 1-
1+ 1-
Aqueous potassium iodide reacts with aqueous lead(II) nitrate.
Step 3
KI (aq)
+
Pb(NO3)2 (aq)
→
PbI2
+
KNO3
2
2
Aqueous potassium iodide reacts with aqueous lead(II) nitrate.
Now what?
An important part of writing double replacement reactions is determining if the reaction will occur or not. To do this, we need to identify the states of the products using the solubility chart.
KI (aq)
+
Pb(NO3)2 (aq)
→
PbI2 (?)
+
KNO3 (?)
2
2
Predicting solubility
Let’s first look at the lead(II) iodide. According to the solubility chart, is it soluble or insoluble in water?
PbI2 (?)
Predicting solubility
It looks like it’s insoluble meaning that it is a solid when in water. The ions remain bonded and are not free to move around the solution and you will see it as a precipitate.
PbI2 (s)
Predicting solubility
Let’s now look at the solubility of the other product in this reaction, potassium nitrate.
KNO3 (?)
Predicting solubility
This one looks like it’s soluble. That means that the ions remain dissociated in the solution. You will not see this compound form in this reaction.
KNO3 (aq)
Predicting solubility
Because at least one of the products is a solid, this reaction WILL occur. You will see the lead(II) iodide precipitate which is evidence of a chemical reaction.
KI (aq)
+
Pb(NO3)2 (aq)
→
PbI2 (s)
+
KNO3 (aq)
2
2
This format is called the molecular equation, an equation showing the complete neutral formulas for each compound in the reaction as if they existed as molecules.
Practice
Aqueous copper(II) sulfate and aqueous sodium carbonate
Step 1: Write reactant formulas
CuSO4(aq) + Na2CO3(aq) →
Step 2: Swap cations and write formulas for products
CuSO4(aq) + Na2CO3(aq) →
Na2SO4(?) + CuCO3(?)
Step 3: Balance the equation
CuSO4(aq) + Na2CO3(aq) →
Na2SO4(?) + CuCO3(?)
The equation is already balanced.
Step 4: Predict states of products
CuSO4(aq) + Na2CO3(aq) →
Na2SO4(?) + CuCO3(?)
Step 4: Predict states of products
CuSO4(aq) + Na2CO3(aq) →
Na2SO4 + CuCO3(?)
(aq)
Step 4: Predict states of products
CuSO4(aq) + Na2CO3(aq) →
Na2SO4(aq) + CuCO3(?)
Step 4: Predict states of products
CuSO4(aq) + Na2CO3(aq) →
Na2SO4(aq) + CuCO3
(s)
Conclusion: Does the reaction occur?
CuSO4(aq) + Na2CO3(aq) →
Na2SO4(aq) + CuCO3(s)
The reaction does occur because at least one of the products is a solid.
Last Practice: On Your Own
When a solution of sodium hydroxide is mixed with a solution of lead(II) nitrate, will a reaction occur? Write the balanced molecular chemical equation for the reaction.
Last Practice: On Your Own
NaOH (aq) + Pb(NO3)2 (aq) →
NaNO3 (?) + Pb(OH)2 (?)
Last Practice: On Your Own
2 NaOH (aq) + Pb(NO3)2 (aq) →
2 NaNO3 (?) + Pb(OH)2 (?)
Last Practice: On Your Own
2 NaOH (aq) + Pb(NO3)2 (aq) →
2 NaNO3 (aq) + Pb(OH)2 (s)
Yes, a reaction occurs because lead(II) hydroxide is a precipitate