STATICS - Lecture Notes / Mehmet Zor
1
23 Agust 2024
3- EQUILIBRIUM
y
D
x
C
E
z
2m
3m
B
A
1m
4m
2m
Figure 3.68
STATICS - Lecture Notes / Mehmet Zor
2
23 Agust 2024
P
F
z
Forces of P = 3kN and F = 4kN are applied to point E of the EDCOB rod, which is bent as shown in the figure. The rod is kept in equilibrium by bearings C, D and the BA cable. Both bearings do not allow translation in any axis. The reaction moments in the bearings can be neglected. Accordingly, calculate the tensile force T that occurs in the BA cable. Answer: T=3.11kN
Question 3.13(*)
3- EQUILIBRIUM
Figure 3.69
STATICS - Lecture Notes / Mehmet Zor
3
23 Agust 2024
The homogeneous cover in the figure weighs 20kN and its center of gravity is point G, which is its exact middle point. The cover is connected to the wall with hinges at A and B and is additionally balanced with a CD cable. (Point D is fixed to the wall.) Frictions and all moment reactions in the hinges can be neglected. Also, hinge A allows movement in the x direction. Accordingly, calculate the force that occurs in the CD cable with a vector solution.Answer: TCD = 20.83kN
Question 3.14
Figure 3.70
STATICS - Lecture Notes / Mehmet Zor
4
23 Agust 2024
3m
4.5m
6m
1m
E
F = 2kN
A
C
B
D
H
x
y
z
2.5m
2.5m
A force of F = 2kN parallel to the y-axis is applied to the frame in the figure from point E. This force is balanced by the spherical joint at A, the cable CD and the ring at B. The ring B allows rotation and translation in the direction of HB. Neglecting all frictions,
a-) Find the force in the cable CD,
b-) Find the reactions in the connections A and B.
Question 3.15
Answers: a-) TCD = 2.85kN,
b-) Bx =0.27kN, Bz=4.037kN, Ax=-1.253kN, Ay=-3.026kN, Az=-1.53kN
3- EQUILIBRIUM
Figure 3.71
STATICS - Lecture Notes / Mehmet Zor
5
23 Agust 2024
A load of F = 600 N is applied to the corner G of a rigid pipe bent as shown in the figure. The pipe is connected to the floor at E and to the vertical wall at C with a ball joint, and at B it is fixed to the wall with the help of BA cable. Accordingly, find the magnitude of the force generated in the BA cable. Answer: 409.2 N
3- EQUILIBRIUM
Question 3.16
Figure 3.72
STATICS - Lecture Notes / Mehmet Zor
6
23 Agust 2024
A 2000N load is hung from the end of the rigid ABC triangle element. The load is kept in equilibrium at the position shown in the figure by a spherical (ball) joint at point A and the cables BD and BE. (Points D and E are in the xz plane.) Find the forces in the cables and the resultant of the reactions at point A.
Answers: TBD= 2360N, TBE = 820N, A =4766.5N
3- EQUILIBRIUM
Question 3.17
Figure 3.73
STATICS - Lecture Notes / Mehmet Zor
7
23 Agust 2024
When the 20kg door is opened, a 15kg H weight attached to the HEC rope is used to automatically close it. Calculate the force P that must be applied perpendicularly to the D knob and the reaction forces that occur in A and its hinges in order to keep the door open at θ = 90o.
(Hinge A allows movement in the vertical direction. g=9.81m/s2)
Answers: P= 118.9N, A=82N, B=222.26N
3- EQUILIBRIUM
Question 3.18
Figure 3.74