Operations Planning and Scheduling
Chapter 10
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-1
What is Operations Planning and Scheduling?
Operations planning and scheduling
The process of balancing supply with demand, from the aggregate level down to the short-term scheduling level
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-2
Operations Planning and Scheduling
TYPES OF PLANS WITH OPERATIONS PLANNING AND SCHEDULING | |
Term | Definition |
Sales and operations plan (S&OP) | A time-phased plan of future aggregate resource levels so that supply is in balance with demand |
Aggregate plan | Another term for the sales and operations plan |
Production plan | A sales and operations plan for a manufacturing firm that centers on production rates and inventory holdings |
Staffing plan | A sales and operations plan for a service firm, which centers on staffing and on other human resource-related factors |
Resource plan | An intermediate step in the planning process that lies between S&OP and scheduling |
Schedule | A detailed plan that allocates resources over shorter time horizons to accomplish specific tasks |
Table 10.1
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-3
Levels in Operations Planning and Scheduling
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-4
Levels in Operations Planning and Scheduling
Business or
annual plan
Scheduling
Resource Planning
Sales
Plan
Operations
Plan
Sales and Operations Plan
Forecasting
Operations
strategy
Constraint
management
Figure 10.2
Level 1
Level 2
Level 3
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-5
Levels in Operations Planning and Scheduling
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-6
S&OP Supply Options
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-7
S&OP Strategies
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-8
S&OP Strategies
TYPES OF COSTS WITH SALES AND OPERATIONS PLANNING | |
Cost | Definition |
Regular time | Regular-time wages plus benefits and pay for vacations |
Overtime | Wages paid for work beyond the normal workweek exclusive of fringe benefits |
Hiring and layoff | Cost of advertising jobs, interviews, training programs, scrap caused by inexperienced employees, exit interviews, severance pay, and retraining |
Inventory holding | Capital, storage and warehousing, pilferage and obsolescence, insurance, and taxes |
Backorder and stockout | Costs to expedite past-due orders, potential cost of losing a customer |
Table 10.2
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-9
S&OP Strategies
Figure 10.3
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-10
S&OP Strategies
Finalize
and communicate
6
Executive S&OP meeting
5
Consensus meeting
4
Update
S&OP spreadsheets
3
Demand planning
2
Gather data
1
Steps in Sales and Operations Planning Process
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-11
Spreadsheet for a Manufacturer
Figure 10.4
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-12
Example 10.1
| 1 | 2 | 3 | 4 | 5 | 6 | Total |
Forecasted demand | 6 | 12 | 18 | 15 | 13 | 14 | 78 |
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-13
Example 10.1
Currently, 10 part-time clerks are employed. They have not been subtracted from the forecasted demand shown. Constraints and cost information are as follows:
a. The size of training facilities limits the number of new hires in any period to no more than 10.
b. No backorders are permitted; demand must be met each period.
c. Overtime cannot exceed 20 percent of the regular-time capacity in any period. The most that any part-time employee can work is 1.20(20) = 24 hours per week.
d. The following costs can be assigned:
Regular-time wage rate $2,000/time period at 20 hrs/week
Overtime wages 150% of the regular-time rate
Hires $1,000 per person
Layoffs $500 per person
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-14
Example 10.1
a. Chase Strategy
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-15
Example 10.1
Figure 10.5
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-16
Example 10.1
b. Level Strategy
1.20w = 18 employees required in peak period (period 3)
w =
= 15 employees
18
1.20
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-17
Example 10.1
Figure 10.6
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-18
Application 10.1
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-19
Application 10.1
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-20
Application 10.1
| Quarter | | |||
| 1 | 2 | 3 | 4 | Total |
Forecasted demand (hrs) | 6,000 | 12,000 | 19,000 | 9,000 | 46,000 |
Workforce level (workers) | 12 | | | | 91 |
Undertime (hours) | 240 | | | | 1,320 |
Overtime (hours) | 0 | | | | 0 |
Utilized time (hours) | 6,000 | | | | 46,000 |
Hires (workers) | 1 | | | | 26 |
Layoffs (workers) | 0 | | | | 19 |
37 |
240 |
0 |
19,000 |
13 |
0 |
18 |
360 |
0 |
9,000 |
0 |
19 |
24 |
480 |
0 |
12,000 |
12 |
0 |
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-21
Application 10.1
What is the total cost of this plan?
Costs per Quarter | |||||
| 1 | 2 | 3 | 4 | Total |
Utilized time | $72,000 | | | | $552,000 |
Undertime | 2,880 | | | | 15,840 |
Overtime | 0 | | | | 0 |
Hires | 3,000 | | | | 78,000 |
Layoffs | 0 | | | | 38,000 |
| | | Total Cost | $683,840 | |
$144,000 |
5,760 |
0 |
36,000 |
0 |
$228,000 |
2,880 |
0 |
39,000 |
0 |
$108,000 |
4,320 |
0 |
0 |
38,000 |
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-22
Application 10.2
1.20w =
w = 30.45 or 31 employees
36.54 employee-period equivalents
19,000
520
=
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-23
Application 10.2
Quarter | |||||
| 1 | 2 | 3 | 4 | Total |
Forecasted demand (hrs) | 6,000 | 12,000 | 19,000 | 9,000 | 46,000 |
Workforce level (workers) | 31 | | | | |
Undertime (hours) | 10,120 | | | | |
Overtime (hours) | 0 | | | | |
Utilized time (hours) | 6,000 | | | | |
Hires (workers) | 20 | | | | |
Layoffs (workers) | 0 | | | | |
31 |
4,120 |
0 |
12,000 |
0 |
0 |
31 |
0 |
2,880 |
16,120 |
0 |
0 |
31 |
7,120 |
0 |
9,000 |
0 |
0 |
124 |
21,360 |
2,880 |
43,120 |
20 |
0 |
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-24
Application 10.2
What is the total cost of this level workforce plan?
Costs per Quarter | |||||
| 1 | 2 | 3 | 4 | Total |
Utilized time | $72,000 | | | | $517,440 |
Undertime | 121,440 | | | | 256,320 |
Overtime | 0 | | | | 51,840 |
Hires | 60,000 | | | | 60,000 |
Layoffs | 0 | | | | 0 |
| | | Total Cost | $885,600 | |
$108,000 |
85,440 |
0 |
0 |
0 |
$193,440 |
0 |
51,840 |
0 |
0 |
$144,000 |
49,440 |
0 |
0 |
0 |
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-25
Application 10.3
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-26
Application 10.3
Quarter | |||||
| 1 | 2 | 3 | 4 | Total |
Forecasted demand | 6,000 | 12,000 | 19,000 | 9,000 | 46,000 |
Workforce level | | | | | |
Undertime (hours) | | | | | |
Overtime (hours) | | | | | |
Utilized time (hours) | | | | | |
Hires (workers) | | | | | |
Layoffs (workers) | | | | | |
12 |
240 |
0 |
6,000 |
1 |
0 |
85 |
1,080 |
2,880 |
43,120 |
20 |
13 |
24 |
480 |
0 |
12,000 |
12 |
0 |
31 |
0 |
2,880 |
16,120 |
7 |
0 |
18 |
360 |
0 |
9,000 |
0 |
13 |
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-27
Application 10.3
Costs per Quarter | |||||
| 1 | 2 | 3 | 4 | Total |
Utilized time | $72,000 | $144,000 | $193,440 | $108,000 | $517,440 |
Undertime | | | | | |
Overtime | | | | | |
Hires | | | | | |
Layoffs | | | | | |
| | | Total Cost | | |
What is the cost of your mixed strategy plan?
12,960 |
51,840 |
60,000 |
26,000 |
$668,240 |
|
2,880 |
0 |
3,000 |
0 |
5,760 |
0 |
36,000 |
0 |
0 |
51,840 |
21,000 |
0 |
4,320 |
0 |
0 |
26,000 |
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-28
Scheduling
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-29
Scheduling
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-30
Scheduling
Gantt Progress Chart
Nissan
Ford
Pontiac
Job
4/20
4/22
4/23
4/24
4/25
4/26
4/21
4/17
4/18
4/19
Current date
Start activity
Finish activity
Scheduled activity time
Actual progress
Nonproductive time
Figure 10.7
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-31
Scheduling
Operating Room A
Workstation
7am
Operating Room B
Operating Room C
12 pm
8am
9am
10am
11am
1pm
2pm
3pm
4pm
5pm
6pm
Time
Dr. Gary Case
Dr. Jeff Dow
Dr. Madeline Easton
Dr. Dan Gillespie
Dr. Jordanne Flowers
Dr. Jon Adams
Dr. Aubrey Brothers
Dr. Alaina Bright
Gantt Workstation Chart
Figure 10.8
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-32
Scheduling
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-33
Scheduling
Step 1: Find all the pairs of consecutive days
Step 2: If a tie occurs, choose one of the tied pairs, consistent with the provisions written into the labor agreement
Step 3: Assign the employee the selected pair of days off
Step 4: Repeat steps 1 – 3 until all of the requirements have been satisfied
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-34
Example 10.2
The Amalgamated Parcel Service is open seven days a week. The schedule of requirements is:
Day | M | T | W | Th | F | S | Su |
Required number of employees | 6 | 4 | 8 | 9 | 10 | 3 | 2 |
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-35
Example 10.2
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-36
Example 10.2
Scheduling Days Off | ||||||||
M | T | W | Th | F | S | Su | Employee | Comments |
6 | 4 | 8 | 9 | 10 | 3 | 2 | 1 | The S–Su pair has the lowest total requirements. Assign Employee 1 to a M-F schedule. |
5 | 3 | 7 | 8 | 9 | 3 | 2 | 2 | The S–Su pair has the lowest total requirements. Assign Employee 2 to a M-F schedule. |
4 | 2 | 6 | 7 | 8 | 3 | 2 | 3 | The S–Su pair has the lowest total requirements. Assign Employee 3 to a M-F schedule. |
3 | 1 | 5 | 6 | 7 | 3 | 2 | 4 | The M–T pair has the lowest total requirements. Assign Employee 4 to a W-Su schedule. |
3 | 1 | 4 | 5 | 6 | 2 | 1 | 5 | The S–Su pair has the lowest total requirements. Assign Employee 5 to a M-F schedule. |
2 | 0 | 3 | 4 | 5 | 2 | 1 | 6 | The M–T pair has the lowest total requirements. Assign Employee 6 to a W-Su schedule. |
2 | 0 | 2 | 3 | 4 | 1 | 0 | 7 | The S–Su pair has the lowest total requirements. Assign Employee 7 to a M-F schedule. |
1 | 0 | 1 | 2 | 3 | 1 | 0 | 8 | Four pairs have the minimum requirement and the lowest total. Choose the S–Su pair according to the tie-breaking rule. Assign Employee 8 to a M-F schedule. |
0 | 0 | 0 | 1 | 2 | 1 | 0 | 9 | Arbitrarily choose the Su–M pair to break ties because the S–Su pair does not have the lowest total requirements. Assign Employee 9 to a T-S schedule. |
0 | 0 | 0 | 0 | 1 | 0 | 0 | 10 | Choose the S–Su pair according to the tie-breaking rule. Assign Employee 10 to a M-F schedule. |
The S–Su pair has the lowest total requirements. Assign Employee 1 to a M-F schedule. |
The S–Su pair has the lowest total requirements. Assign Employee 2 to a M-F schedule. |
The S–Su pair has the lowest total requirements. Assign Employee 3 to a M-F schedule. |
6 | 4 | 8 | 9 | 10 | 3 | 2 | 1 |
5 | 3 | 7 | 8 | 9 | 3 | 2 | 2 |
4 | 2 | 6 | 7 | 8 | 3 | 2 | 3 |
3 | 1 | 5 | 6 | 7 | 3 | 2 | 4 | The M–T pair has the lowest total requirements. Assign Employee 4 to a W-Su schedule. |
3 | 1 | 4 | 5 | 6 | 2 | 1 | 5 | The S–Su pair has the lowest total requirements. Assign Employee 5 to a M-F schedule. |
2 | 0 | 3 | 4 | 5 | 2 | 1 | 6 | The M–T pair has the lowest total requirements. Assign Employee 6 to a W-Su schedule. |
2 | 0 | 2 | 3 | 4 | 1 | 0 | 7 | The S–Su pair has the lowest total requirements. Assign Employee 7 to a M-F schedule. |
1 | 0 | 1 | 2 | 3 | 1 | 0 | 8 | Four pairs have the minimum requirement and the lowest total. Choose the S–Su pair according to the tie-breaking rule. Assign Employee 8 to a M-F schedule. |
0 | 0 | 0 | 1 | 2 | 1 | 0 | 9 | Arbitrarily choose the Su–M pair to break ties because the S–Su pair does not have the lowest total requirements. Assign Employee 9 to a T-S schedule. |
0 | 0 | 0 | 0 | 1 | 0 | 0 | 10 | Choose the S–Su pair according to the tie-breaking rule. Assign Employee 10 to a M-F schedule. |
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-37
Example 10.2
| Final Schedule | | ||||||
Employee | M | T | W | Th | F | S | Su | Total |
1 | X | X | X | X | X | off | off | |
2 | X | X | X | X | X | off | off | |
3 | X | X | X | X | X | off | off | |
4 | off | off | X | X | X | X | X | |
5 | X | X | X | X | X | off | off | |
6 | off | off | X | X | X | X | X | |
7 | X | X | X | X | X | off | off | |
8 | X | X | X | X | X | off | off | |
9 | off | X | X | X | X | X | off | |
10 | X | X | X | X | X | off | off | |
Capacity, C | 7 | 8 | 10 | 10 | 10 | 3 | 2 | 50 |
Requirements, R | 6 | 4 | 8 | 9 | 10 | 3 | 2 | 42 |
Slack, C – R | 1 | 4 | 2 | 1 | 0 | 0 | 0 | 8 |
In this example, Friday always has the maximum requirements and should be avoided as a day off.
The final schedule for the employees is shown in the following table.
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-38
Sequencing Jobs at a Workstation
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-39
Example 10.3
Customer | Time Since Order Arrived (days ago) | Processing Time (days) | Due Date�(days from now) |
A | 15 | 25 | 29 |
B | 12 | 16 | 27 |
C | 5 | 14 | 68 |
D | 10 | 10 | 48 |
E | 0 | 12 | 80 |
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-40
Example 10.3
27 | 14 |
12 | 53 |
41 | + | 10 | = | 51 | 48 | 3 | 10 | 61 |
51 | + | 14 | = | 65 | 68 | 0 | 5 | 70 |
65 | + | 12 | = | 77 | 80 | 0 | 0 | 77 |
15 | 40 |
+ | 25 | = | 25 |
29 | 0 |
0 |
25 |
+ | 16 | = | 41 |
Customer Sequence | Start Time (days) | | Processing Time (days) | | Finish Time (days) | Due Date | Days Past Due | Days Ago Since Order Arrived | Flow Time (days) |
A | | | | | | | | | |
B | | | | | | | | | |
D | | | | | | | | | |
C | | | | | | | | | |
E | | | | | | | | | |
Customer E’s order arrived today, so it is processed last.
The sequence is shown in the following table, along with the days past due and flow times.
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-41
Example 10.3
The finish time for a job is its start time plus the processing time. Its finish time becomes the start time for the next job in the sequence, assuming that the next job is available for immediate processing. The days past due for a job is zero (0) if its due date is equal to or exceeds the finish time. Otherwise it equals the shortfall. The flow time for each job equals its finish time plus the number of days ago since the order first arrived at the workstation. The days past due and average flow time performance measures for the FCFS schedule are
Average days past due =
Average flow time =
= 3.4 days
= 60.2 days
0 + 14 + 3 + 0 + 0
5
40 + 53 + 61 + 70 + 77
5
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-42
Example 10.3
b. Using the STP rule, the average flow time can be reduced with this new sequence.
0 | + | 10 | = | 10 |
Customer Sequence | Start Time (days) | | Processing Time (days) | | Finish Time (days) | Due Date | Days Past Due | Days Ago Since Order Arrived | Flow Time (days) |
D | | | | | | | | | |
E | | | | | | | | | |
C | | | | | | | | | |
B | | | | | | | | | |
A | | | | | | | | | |
Average days past due =
Average flow time =
= 14.6 days
= 47.8 days
0 + 0 + 0 + 25 + 48
5
20 + 22 + 41 + 64 + 92
5
22 | + | 14 | = | 36 | 68 | 0 | 5 | 41 |
36 | + | 16 | = | 52 | 27 | 25 | 12 | 64 |
52 | + | 25 | = | 77 | 29 | 48 | 15 | 92 |
48 | 0 |
10 | 20 |
10 | + | 12 | = | 22 |
80 | 0 |
0 | 22 |
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-43
Application 10.4
A consulting company has five jobs in its backlog. A schedule was created using the FCFS rule and the average days past due was 3.4 days and the average flow time was 60.2 days. Create a new schedule using the EDD rule, calculating the average days past due and flow time. In this case, does EDD outperform the FCFS rule?
Customer | Time Since Order �Arrived (days ago) | Processing �Time (days) | Due Date �(days from now) |
A | 15 | 25 | 29 |
B | 12 | 16 | 27 |
C | 5 | 14 | 68 |
D | 10 | 10 | 48 |
E | 0 | 12 | 80 |
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-44
Application 10.4
Customer Sequence | Start Time (days) | | Processing Time (days) | | Finish Time (days) | Due Date | Days Past Due | Days Ago Since Order Arrived | Flow Time (days) |
B | | | | | | | | | |
A | | | | | | | | | |
D | | | | | | | | | |
C | | | | | | | | | |
E | | | | | | | | | |
0 | + | 16 | = | 16 |
41 | + | 10 | = | 51 | 48 | 3 | 10 | 61 |
51 | + | 14 | = | 65 | 68 | 0 | 5 | 70 |
65 | + | 12 | = | 77 | 80 | 0 | 0 | 77 |
27 | 0 |
12 | 28 |
16 | + | 25 | = | 41 |
29 | 12 |
15 | 56 |
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-45
Application 10.4
The days past due and average flow time performance measures for the EDD schedule are:
By both measures, EDD outperforms the FCFS.
However, the solution found in Example 15.3 still has the best average flow time of only 47.8 days
Average days past due =
Average flow time =
= 3.0 days
= 58.4 days
0 + 12 + 3 + 0 + 0
5
28 + 56 + 61 + 70 + 77
5
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-46
Software Support
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-47
Solved Problem 1
Planning Period | 1 | 2 | 3 | 4 |
Demand (hours) | 21,000 | 18,000 | 30,000 | 12,000 |
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-48
Solved Problem 1
Cranston pays regular-time wages of $6,000 per employee per period for any time worked up to 600 hours (including undertime). The overtime pay rate is $15 per hour over 600 hours. Hiring, training, and outfitting a new employee costs $8,000. Layoff costs are $2,000 per employee. Currently, 40 employees work for Cranston in this capacity. No delays in service, or backorders, are allowed.
a. Prepare a chase strategy using only hiring and layoffs. What are the total numbers of employees hired and laid off?
b. Develop a workforce plan that uses the level strategy, relaying only on overtime and undertime. Maximize the use of overtime during the peak period so as to minimize the workforce level and amount of undertime.
c. Propose an effective mixed-strategy plan.
d. Compare the total costs of the three plans.
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-49
Solved Problem 1
a. Chase Strategy
Figure 10.9
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-50
Solved Problem 1
b. Level Strategy
Figure 10.10
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-51
Solved Problem 1
Figure 10.11
c. Mixed Strategy
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-52
Solved Problem 1
d. Total Cost of Plans
CHASE = $1,050,000
LEVEL = $1,119,000
MIXED = $1,021,000
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-53
Solved Problem 2
Day | M | T | W | Th | F | S | Su |
Number of Clerks Required | 3 | 4 | 5 | 5 | 4 | 7 | 8 |
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-54
Solved Problem 2
Bulger now has to come up with a workforce schedule that guarantees each checkout clerk two consecutive days off but still covers all requirements.
a. Develop a workforce schedule that covers all requirements while giving two consecutive days off to each clerk. How many clerks are needed? Assume that the clerks have no preference regarding which days they have off.
b. Plans can be made to use the clerks for other duties if slack or idle time resulting from this schedule can be determined. How much idle time will result from this schedule, and on what days?
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-55
Solved Problem 2
The minimum number of clerks is eight.
3 | 4 | 5 | 5 | 4 | 7 | 8 |
off | off | X | X | X | X | X |
3 | 4 | 4 | 4 | 3 | 6 | 7 |
off | off | X | X | X | X | X |
| | | | Day | | | |
| M | T | W | Th | F | S | Su |
Requirements | | | | | | | |
Clerk 1 | | | | | | | |
Requirements | | | | | | | |
Clerk 2 | | | | | | | |
Requirements | | | | | | | |
Clerk 3 | | | | | | | |
Requirements | | | | | | | |
Clerk 4 | | | | | | | |
3 | 4 | 3 | 3 | 2 | 5 | 6 |
X | X | X | off | off | X | X |
2 | 3 | 2 | 3 | 2 | 4 | 5 |
X | X | X | off | off | X | X |
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-56
Solved Problem 2
1 | 2 | 1 | 3 | 2 | 3 | 4 |
X | off | off | X | X | X | X |
0 | 2 | 1 | 2 | 1 | 2 | 3 |
off | off | X | X | X | X | X |
0 | 2 | 0 | 1 | 0 | 1 | 2 |
X | X | off | off | X | X | X |
0 | 1 | 0 | 1 | 0 | 0 | 1 |
X | X | X | X | off | off | X |
0 | 0 | 0 | 0 | 0 | 0 | 0 |
| | | | Day | | | |
| M | T | W | Th | F | S | Su |
Requirements | | | | | | | |
Clerk 5 | | | | | | | |
Requirements | | | | | | | |
Clerk 6 | | | | | | | |
Requirements | | | | | | | |
Clerk 7 | | | | | | | |
Requirements | | | | | | | |
Clerk 8 | | | | | | | |
Requirements | | | | | | | |
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-57
Solved Problem 2
b. Based on the results in part (a), the number of clerks on duty minus the requirements is the number of idle clerks available for other duties:
| M | T | W | Th | F | S | Su |
Number on duty | 5 | 4 | 6 | 5 | 5 | 7 | 8 |
Requirements | 3 | 4 | 5 | 5 | 4 | 7 | 8 |
Idle clerks | 2 | 0 | 1 | 0 | 1 | 0 | 0 |
Copyright ©2016 Pearson Education, Inc. All rights reserved.
10-58