The Second Law of Thermodynamics
The Old Guitarist, Pablo Picasso, 1904
1st Law of Thermodynamics
Energy cannot be created or destroyed.
Reminder
Which arrow shows what happens “spontaneously”
to a bedroom over time?
Which arrow shows what happens “spontaneously”
to a bedroom over time?
Occurs spontaneously
Requires Energy
Which of the following processes occur spontaneously?
Tricky! Depends on the temperature!
Thermodynamic Favorability
A physical or chemical process is spontaneous (thermodynamically favorable) if it can proceed on its own without any outside energy input in a given set of conditions.
Spontaneous Process
=
Thermodynamically Favorable Process
spontaneous
above 0oC
spontaneous
below 0oC
Spontaneity does not refer to kinetics
�Important note: the spontaneity of a chemical reaction (thermodynamics) is not related to the speed (kinetics) of the chemical reaction.
Example:
C(diamond) + O2(g) 🡪 CO2(g)
slow (almost impossibly slow) reaction
but
thermodynamically favorable
kinetics
thermo
Determinants of Spontaneity
Two factors determine whether a reaction is spontaneous:
?!?
What the heck is
Entropy
Examples of increasing entropy:
What do these have in common?
Entropy
Entropy
What factors could be changed for a system that would increase the entropy of the system?
Entropy
What factors could be changed for a system that would increase the entropy of the system?
Entropy
What factors could be changed for a system that would increase the entropy of the system?
Entropy
What factors could be changed for a system that would increase the entropy of the system?
The 2nd and 3rd Laws of Thermodynamics
The laws of thermodynamics address entropy:
3rd Law of Thermodynamics
The entropy of a perfect crystal is 0 J/K at absolute zero.
Mom, according to the 3rd Law of Thermodynamics, it will never be cold enough for this room to get cleaned up.
2nd Law of Thermodynamics
For any spontaneous process, the entropy of the universe increase.
∆Suniverse > 0
(This is a big one!)
∆Suniv = Ssys + Ssurr
Hess’s Law and ∆Ssys
Remember Hess’s Law?
∆Ssys = ∑nSproducts - ∑nSreactants
Hess’s Law and ∆Ssys
Try this:
What is ∆Sorxn for the reaction shown below?
2 H2(g) + O2(g) 🡪 2 H2O(g)
From experimental data:
SoH2(g) = 130.7 J/molK
SoO2(g) = 205.2 J/molK
SoH2O(g) = 188.8 J/molK
∆Ssys = ∑nSproducts - ∑nSreactants
∆Sorxn = (2molx188.8 J/molK) – ((2molx130.7 J/molK) +
(1molx205.2 J/molK))
∆Sorxn = -89.00 J/K
Did we just break the law?
The previous example is a thermodynamically favorable reaction. But its ∆Sorxn was -89 J/K.