1 of 1

The above Question can also be solved in the following way

For any positive integer n,

prove that n3 n is divisible by 6.

Hint : n3n = n

(n2 – 1)

(n – 1)

= n

=

(n + 1)

(n)

……..Since, (a2b2) = (ab)(a + b)

Q.

(n + 1)

(n – 1)

Prove that product of three consecutive positive integers is divisible by 6.

Q.

Sol.