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ELECTRICAL MACHINE QUIZ_89
DC MOTOR_02
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Q.16 In case of motor, the induced emf is known as
1 point
armature reaction
back emf
reactance voltage
All of the above
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Q.17 The back emf oppose the
1 point
terminal voltage
induced emf
applied voltage
circulating current
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Q.18 The back emf induced in motor is
1 point
due to motor action
due to generator action
due to engine
all of the above
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Q.19 Back emf is also known as
1 point
induced emf
counter emf
generated emf
all of the above
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Q.20 The correct expression of back emf is
1 point
Eb = NPфZ/ 60
Eb = NPфZ/ 120A
Eb = NPфZ/ 60A
Eb = NPфZA/ 60
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Q.21The back emf of the motor is
1 point
always greater than its terminal voltage
always equal to its terminal voltage
always less than its terminal voltage
any of the above
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Q.22 In motor, current flows from the __
1 point
line into the armature to add the generated voltage
armature into the line
line into the armature against the generated voltage
line into the armature to oppose the generated voltage
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Q.23 The terminal voltage of the motor is given by
1 point
V = Eb + Ia Ra
V = Eb + Vdrop armature
V = Egen + Ia Ra
Both A and B
[V= motor terminal voltage, E= generated emf, Eb = back emf]
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Q.24 When a dc machine is loaded either as a motor or generator, the ___ carry current.
1 point
stater conductor
rotor conductor
field conductor
all of the above
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Q.25 In rotor the conductor lie ____ of the rotor at a common radius from its center
1 point
near the centre
near the surface
in between
anywhere
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Q.26 The torque produce around the ____ of the rotor and the rotor starts rotating
1 point
radius
diameter
circumference
area
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Q.27 When the machine is operates as a generator at constant speed, the torque is
1 point
equal and same as that of provided by the prime-mover
equal and opposite to that of provided by the prime-mover
unequal and same as that of provided by the prime-mover
unequal and opposite to that of provided by the prime-mover
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Q.28 The expression of mechanical power developed by the armature is
1 point
Pm = τav
Pm = ωτav
Pm = 2лnτav
Both B and C
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Q.29The average torque is given by
1 point
τav = PZф / 2лA
τav = PZфIa / 2A
τav = PZфIa / 2л
τav = PZфIa / 2лA
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Q.30which of the following is electrical equivalent of gross mechanical power developed by the armature?
1 point
EIa
I2a Ra
VIa
E
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