JavaScript isn't enabled in your browser, so this file can't be opened. Enable and reload.
Basic Concepts of Chemistry- 05 (Mole)
Sign in to Google
to save your progress.
Learn more
* Indicates required question
Email
*
Your email
Name of Student
*
Your answer
School and City
*
Your answer
Q1. Find the number of moles and number of atoms of H and S in 10 mole of H2S.
*
1 point
1.8066 x 10^23 S atoms
6.022 x 10^23 S atoms
6.022×10^24 S atoms
12.044 x 10^23 S atoms
Q2. Calculate the number of atoms of each element in 245 g of KClO3.
*
1 point
12.044×10^23 K atoms, 12.044×10^23 Cl atoms and 1.806×10^24 O atoms.
12.044×10^24 K atoms, 12.044×10^22 Cl atoms and 1.806×10^24 O atoms.
12.044×10^21 K atoms, 12.044×10^24 Cl atoms and 1.806×10^22 O atoms.
12.044×10^20 K atoms, 12.044×10^20 Cl atoms and 1.806×10^25 O atoms.
Q3. If 4 g of NaOH dissolves in 36 g of H2O, calculate the Mole fraction of each component.
*
1 point
H2O = 0.90, NaOH = 0.1
H2O = 0.5, NaOH = 0.5
H2O = 0.95, NaOH = 0.05
H2O = 0.45, NaOH = 0.55
Q4. Calculate the number of atoms in 12.2 litres of the below gas at NTP (i) mono-atomic (ii) diatomic gas
*
1 point
(i) 3.011×10^23 atoms (ii) 12.044 ×10^23 atoms
(i) 3.011×10^23 atoms (ii) 2 x 3.011×10^23 atoms
(i) 2 x 3.011×10^23 atoms (ii) 3.011×10^23 atoms
(i) 6.022×10^23 atoms (ii) 2 x 3.011×10^23 atoms
Q5. If a mole were to contain 1×1024 particles, what would be the mass of (i) one mole of oxygen(ii) a single oxygen molecule?
*
1 point
(i) 8 (ii) 6.4 x 10^-23
(i) 32 (ii) 3.2 x 10^-23
(i) 16 (ii) 3.2 x 10^-20
(i) 16 (ii) 3.2 x 10^-24
Q6. Calculate the standard molar volume of oxygen gas. The density of O2 gas at NTP is 1.429 g/L.
*
1 point
22.39 L
44.8 L
6.88 L
2.24 L
Q7. if 2 mol of Calcium Carbonate (Formula Weight =100) occupies a volume of 67.0 ml, Find the density ?
*
1 point
2.99 gm/ml
1.5 gm/ml
6.05 gm/ml
3.5 gm/ml
Q8. Calculate how many methane molecules are there in 25 g of Methane?
*
1 point
9.411×10^23 molecules
6.022×10^23 molecules
12.044×10^23 molecules
3.011×10^23 molecules
Q9. Calculate the total number of electrons present in 3.2 g of CH4.
*
1 point
12.044×10^23 electrons.
3.011×10^23 electrons.
6.022×10^23 electrons.
24 ×10^23 electrons.
Q10. State the number of atoms in 1 g atom of Aluminium? 6.022×10^23 atoms
*
1 point
3.011×10^23 atoms
1.2×10^23 atoms
6.022×10^23 atoms
2.23×10^22 atoms
A copy of your responses will be emailed to the address you provided.
Submit
Page 1 of 1
Clear form
Never submit passwords through Google Forms.
reCAPTCHA
Privacy
Terms
This content is neither created nor endorsed by Google.
Report Abuse
-
Terms of Service
-
Privacy Policy
Forms
