B.Sc.I e Test 2018-19

Request edit access

JavaScript isn't enabled in your browser, so this file can't be opened. Enable and reload.

Name -

Roll No.-

Mobile No.-

1. The necessary and sufficient conditions for Mdx + Ndy = 0 to be exact is …………

1 point

∂M/∂x=∂N/∂Y

(∂^2 M)/(∂x^2 )+ (∂^2 N)/(∂y^2 )

∂M/∂y= ∂N/∂x

(∂^2 M)/∂x∂y

Clear selection

The integrating factor of the linear differential equation dy/dx+Py=Qis…..

1 point

e^(∫p dx)

e^(∫f(x) dx)

e^x

e^y

Clear selection

If((∂M/∂y-∂N/∂x))/N is a function of x, say f(x) then………….. is an integrating factor .

1 point

e^(∫f(y)dy)

e^(∫f(x)dx)

e^x

e^y

Clear selection

The degree of differential equation ((d^3 y)/ (dx^3 )) + (d^2 y)/(dx^2 )+ 5y = 0……

1 point

Clear selection

If (∂N/∂x-∂M/∂y)/M is a function of y, say f(y) then ………. is an integrating factor.

1 point

e ^∫f (y)dy

e ^∫f(x)dx

e^x

e^y

Clear selection

If the equation Mdx + Ndy = 0 is homogeneous equation in xand y, then I.F. = ………..

1 point

1 /Mx+Ny , provided Mx + Ny ≠ 0

e^(∫f(x)dx)

e^(∫f(y)dy)

1/(Mx-Ny), provided Mx – Ny ≠0

Clear selection

If y = px + exp (p) then its solution is ……………

1 point

Y = cx + exp(p)

y = cx + exp(c)

y = cx + p^c

y = cx + c^e

Clear selection

The differential equation y2 = pxy + f (py/x) can be reduced to clairaut’s form by standard substitution ………..

1 point

X= u and y = v

x2 = u and y2 = v

x – u2 and y = v

x = u and y = v2

Clear selection

The solution of p^2 -3p -10 = 0 is ………….

1 point

(y+ 2x –c) ( y +5x –c) =0

(y + 2x – c) (5y +x + c ) = 0

(y-2x – c) (y +5x – c) = 0

(y + 2x – c) (y – 5x – c) = 0

Clear selection

The value of 1/D^2+1 cosx is ----

1 point

xcosx

xsinx

( x/2) Sin x

-xcosx

Clear selection

Submit

Clear form

Never submit passwords through Google Forms.

This content is neither created nor endorsed by Google. - Terms of Service - Privacy Policy

Does this form look suspicious? Report

Forms