LESSON PLAN
School : SMA Negeri 4 Semarang Curriculume : KTSP Subject : Physics Class/Semester : XI/I Time : 4 X 45’ (2 x Meeting) Subject material :Kinds of collisions and the application of momentum and impulse
concept.
Standard Competence :
1. To analyze the natural phenomenon and its regularly in terms object point. Basic Competence :
1.7 To show the relation between concept of Impulse and Momentum to solve the collision
problems. Indicators : 1st Meeting : To differentiate kinds of collision. 2
nd
Meeting: To solve the problems which is related with the collision quantitifly. Objectives : 1. Students are able to differentiate kinds of collisions. 2. Students are able to solve the problems which is related with the collision quantitifly. Subject material : 1. Kinds of collisions.
a. Perfectly elastic collisions. b. Non elastic collisions. c. Partially elastic collisions. 2. The application of momentum and impulse.
a. Restitution coefficient of fall object. b. Rocket launching. c. Shooting of Bullet from gun or cannon. d. A system which is separated into two parts. Learning method : 1st Meeting : Demonstration, discuss, question and answer. 2
nd
Meeting : Expository, discuss, question and answer. Learning Model : 1st Meeting : Cooperative learning. 2
nd
Meeting : Cooperative learning.
❖ 1
st
Meeting Activity1 : Method is applicable Use ICT Discuss
- √
Demonstration Question and answer
√ √
Individual presentation Group presentation
- √
Assessment activity is applicable Question and answer √ Group presentation √ Learner individual review √ Homework √
Demonstration √ Discuss √ Scenario / teaching and learning process
Content Duration
Teacher Activity
Students Introduction 5 minutes a. Gives greeting and prepare the tools
which is needed in demonstration. b. Gives apperception to students:
What is happen when there are a truck which move with high velocity hit the pedicabe which motionless. How about each velocity after both of them is collision? c. Read the objectives.
- Answer greeting.
- Listen to teacher’s
apperception.
Main activity 80 minutes a. Exploration
- Gives students into several groups. - Distributes the worksheet. - Asks for several students to help
her to do the demonstration. - Does the demonstration. b. Elaboration
- Asks for students to discuss the
question in the worksheet. - Guides students do the worksheet. - Asks for sveral students from each group to present their discuss result. - Explains about the kinds of collisions based on the elasticity of an object. - Gives exercises about the
collisions. - Asks for students to discuss the
exercises with adjacent friend. - Guides students to do the exercises. - Asks for students to write the
answer in the white board. - Gives correct answer to students.
c. Confirmation
- Guides students to make
conclusion. - Gives reward to the most active
students.
- Make group.
- Pay attention to demonstration. - Discuss the question in the
worksheet.
- Present the discuss result.
- Attention to teacher’s
explanation.
- Do the exercises.
- Write the answer in the
white board.
- Make conclusion.
Closure 5 minutes Gives task to study about the next
subject material.
Attention to teaher’s command.
nd ❖ 2
Meeting Activity1 : Method is applicable Use ICT Discuss
-
√
Individual presentation
- √
√
Group presentation
-
Assessment activity is applicable Question and answer √ Group presentation - Learner individual review √ Homework √ Individual presentation - Discuss √ Scenario / teaching and learning process
Content Duration
Game Question and answer
Activity Teacher Students Introduction 5 minutes a. Gives greeting and prepare the tools
which is needed in demonstration. b. Gives apperception to students:
How can the rocket launch? What is the role of the momentum and impulse concept in launching a rocket? c. Read the objectives.
- Answer greeting.
- Listen to teacher’s
apperception.
Main activity 80 minutes a. Exploration
- Explains the application of
momentum and impulse concept. - Gives exercises about the application of momentum and impulse concept.
b. Elaboration
- Guides students do the exercises. - Asks for several students to write
the answer in the white board. - Gives correct answer to students.
c. Confirmation
- Guides students to make
conclusion. - Gives reward to the most active
students.
- Listen to teacher’s
explanation. - Do the exercises.
- Write the answer in the
white board. - Listen to teacher’s
explanation.
- Make conclusion.
Closure 5 minutes Asks to students to study hard and
prepare to the daily test.
Attention to teaher’s command.
Evaluation Gives daily test about Momentum and impulse.
Reflection: Question and answer
Sources : - Haryadi, Bambang. 2009. Fisika Untuk SMA/MA Kelas XI. Jakarta :
about the benefit of study kinds of collisions and the application of momentum and impulse concept.
Pusat Perbukuan, Departemen Pendidikan Nasional. - Sunardi dan Etsa Indra Irawan. 2008. Fisika Bilingual Untuk
SMA/MA Kelas XI Semester 1 dan 2. Bandung : Yrama Widya. - Computer/laptop, LCD, White board.
Assessment Assessment indicator : Technique Instrument 1. Students are able to differentiate kinds of collisions. 2. Students are able to solve the problems which is related
with the collision quantitifly.
Writen test Performance test
Essay Worksheet
Assessment of performance test:
No. Criteria
Group A B …. 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1. Fluency of
presentation 2. Attitude in
presentation 3. Result of discussion
that is presented 4. Cooperation 5. Seriousness in activities
Note: Give sign √ for every criteria 5 = Very good ; 4 = good ; 3 = Enough ; 2 = Bad; 1 = Very Bad
𝑺𝒄𝒐𝒓𝒆 𝟏 =
𝒕𝒐𝒕𝒂𝒍 𝟐𝟓
𝒔𝒄𝒐𝒓𝒆
𝒙𝟏𝟎𝟎
Assessment test : Test :
1. Two balls A and B, each have mass 200 gram and 400 gram. A is rolled to right which have speed is 10 m/s, and B is rolled to left which have speed 5 m/s. If both of the balls is collisions, calculate its momentum? 2. In a football game, a player does the penalty. After the ball is kicked, the ball’s velocity is 60
m/s. If the force of the object is 300 N, and players shoes touch the ball in 0.3 s, determine : a. Impulsee that work to the ball, b. Change of momentum, c. Mass of the ball! 3. A bullet that have 6 gram in mass is fired at a wooden block that have 5 kg in mass. The bullet thouches the block and nets in it. The velocity of the bullet when thouching the block is 210 m/s. Calculate the velocity of the system (block and bullet) after collisions! 4. Two blocks each have mass 2 kg and 4 kg moves in opposite direction, each velocity, v
1
= 6 m/s dan v
2
= 4 m/s. Calculate the velocity of both object if the collisions is perfectly elastic! 5. Explain the application of momentum and impulsee concept in launching the rocket!
The key of test : 1. Given : m
A
= 200 g = 0,2 kg m
B
Score 2
2. Given : v
awal
= 400 g = 0,4 kg v
A
= 10 m/s v
B
= 5 m/s Question: p
total
…? Answer : p
total
= m
A
.v
A
+ m
B
.v
B = (0,2 kg.10 m/s)+( 0,4 kg. 5m/s)
= 4 kg.m/s
= 0 m/s
Score v
akhir
= 60 m/s
2 F = 300 N Δt = 0,3 s Question :
a. I…? b. Δp…? c. m
bola
…? Answer :
a. 𝐼 = 𝐹.∆𝑡 = 300 𝑁. 0.3 𝑠 = 90 𝑁.𝑠 b. ∆𝑝 = 𝐼 = 90 𝑁.𝑠 c. ∆𝑝 = 𝑚
𝑏𝑎𝑙𝑙
− 𝑣
𝑖𝑛𝑖𝑡𝑖𝑎𝑙 90 𝑁.𝑠 = 𝑚
𝑏𝑎𝑙𝑙
3. Given : m
p
𝑣
𝑓𝑖𝑛𝑎𝑙
𝑚 𝑠 = 𝑚
𝑏𝑎𝑙𝑙
60
𝑚
𝑚 𝑠
− 0
𝑠 𝑚
𝑏𝑎𝑙𝑙
. 60
=
60𝑚/𝑠 90 𝑁.𝑠
= 1.5 𝑘𝑔
Score 2
4. Given : m
1
= 6 g = 0,006 kg m
b
= 5 kg v
p
= 210 m/s Question : v’…? Answer :
𝑣
𝑝
= 𝑣’ 𝑚
𝑝
= 𝑣
𝑏 .𝑣
𝑝
+ 𝑚
𝑏
.𝑣
𝑏
= (𝑚
𝑝
+ 𝑚
𝑏
)𝑣’ (0,006𝑘𝑔. 210 𝑚/𝑠) + (5 𝑘𝑔. 0) = (0,006 + 5).𝑣’
1,26 𝑘𝑔.𝑚/𝑠 𝑣’ = =
5,006 1,26 𝑘𝑔.
𝑘𝑔.𝑣’
𝑚 𝑠 5,006 𝑘𝑔 = 0,25 𝑚/𝑠 = 2 kg; m
2
= 4 kg
Score v
1
= 6 m/s v
2
= 4 m/s
2 v
1
= 6 m/s v
2
= 4 m/s
1 2
Question : v
1
’ and v
2
’ when perfectly elastic collisions?
Answer : ➢ Because the type of collisions of both blocks is perfectly elastic collisions, so the
coefficient of restitution, e = 1
𝑒 =
− 𝑣
1
′ − 𝑣
2
′
𝑣
1 − 1 𝑣 1
− 𝑣
2
= = − 𝑣 1
′ − 𝑣
𝑣 2
2
′ − 𝑣
1 𝑣
1
− ′ − 𝑣
𝑣 2
2
′
6 − −4 = − 𝑣
1
′ − 𝑣
2
′
10 = − 𝑣
1
′ − 𝑣
2
′
Momentum 10 = conservation’s −𝑣
1
′ + 𝑣
Law 2
′ … 1
:
2 𝑘𝑔 6
𝑚 𝑠
+ 4 𝑚
𝑘𝑔 1 𝑣
1
+ −4 𝑚
2 𝑚 𝑠 𝑣
2
= 𝑚
1
𝑣
1
′ + 𝑚
2
𝑣
2
′
−4=2𝑣 From the equation (1) and (2) we = 2𝑣 1
′ + 4𝑣
2
′
gets :
1
′ + 4𝑣
2
′ … 2
−𝑣 2𝑣
1
1 ′ ′ + + 4𝑣
𝑣
2
2 ′ = 10 ′ = −4 × 2 ′
+ 2𝑣
2 × 1 − 2𝑣 2𝑣
1
1 ′ ′ = 20
+ 4𝑣
6𝑣 2
′ 2
= ′
−4 = 16
+
−𝑣 −𝑣 𝑣 so 1
′ after 1 1 = ′ ′ + 𝑣 2
′ = 10
𝑣
2
′ = 2.67 𝑚/𝑠
+ 2.67 = 10 −7.33 𝑚/𝑠
collisions both blocks move in direction opposite to the initial direction: −7.33 𝑚/𝑠 2.67 𝑚/𝑠
1 2
5. A rocket that have tank which content hydrogen and oxygen liquid. The result of Burning thus liquid is hot gases which spray out through the tail of rocket. When gases spray out for the rocket, there are changes of gases momentum during certain time (impulsee), so produce the pushing force given rocket to the gases. In launching the rocket, momentum conservation’s law holds, that is when the machine of rocket is turned on, the hot gases resulted from fuel burning gets the downward momentum and the rocket will get a momentum and that has the same magnitude with opposite direction to the hot gases exhaust. And it is appropriate to The Third Newton’s Law.
Score 2
𝒔𝒄𝒐𝒓𝒆 𝑺𝒄𝒐𝒓𝒆 𝟐 =
𝒐𝒇 𝒕𝒉𝒆 𝒄𝒐𝒓𝒓𝒆𝒄𝒕 𝟏𝟎
𝒂𝒏𝒔𝒘𝒆𝒓
𝒙𝟏𝟎𝟎
Minimum Mastery Criteria of Learning : 75
Semarang, Principal of SMA Negeri 4 Semarang Teacher,
Dra. Hj. Srinatun, M.Pd Achmad Solechan, SPd NIP 195705071981032010 NIP 197404212002121003