CLASS THREE MATHS ANNUAL REVISION 23-24

Q1. The smallest 2 digit Odd number is

ANS. The smallest 2-digit odd number is 11.

Q2. The smallest 3 digit Odd number is

ANS. The smallest 3-digit odd number is 111.

Q3. The smallest 2-digit even number is

Ans. The smallest 2-digit even number is 10.

Q4. The smallest 3-digit even number is

Ans. The smallest 3-digit even number is 100.

Q5. The largest 2 digit Odd number is

Ans. The largest 2-digit odd number is 99.

Q6. The largest 3 digit Odd number is

Ans. The largest 3-digit odd number is 999.

Q7. The largest 2-digit even number is

Ans. The largest 2-digit even number is 98

Q8. The largest 3-digit even number is

Ans. The largest 3-digit even number is 998

Q9. 1 Rupee = __________Paise

Ans. 1 Rupee = 100 Paise

Q10 . 11 Rupee = __________Paise

Ans. To convert Rupees to Paise, you multiply by 100 since there are 100 Paise in 1 Rupee.

So 11 Rupee is equal to11 x 100 = 1100 Paise

Q11. 23 Rupee = ________ Paise

Ans. To convert Rupees to Paise, you multiply by 100 since there are 100 Paise in 1 Rupee.

So 23 Rupee is equal to23 x 100 = 2300 Paise

Q12. 37.97 Rupee = __________Paise
Ans. To convert Rupees to Paise, you multiply by 100 since there are 100 Paise in 1 Rupee.

So, 37.97 Rupees is equal to 37.97×100=3797

37.97×100=3797 Paise.

Q13. 1 Paise = __________Rupee

1 Paise is equal to 1/100 (or 0.01) Rupee.

Q14. 64 Paise = __________Rupee

Ans. To convert Paise to Rupees, you divide by 100 since there are 100 Paise in 1 Rupee.

So, 64 Paise is equal to 64/100=0.64

64/100 =0.64 Rupees.

Q15. 5678 Paise = __________Rupee
Ans.
To convert Paise to Rupees, you divide by 100 since there are 100 Paise in 1 Rupee.

So, 5678 Paise is equal to
=56.78

=56.78 Rupees.

Q16. Write the numeral for the following number names. Nine hundred forty-eight

The numeral for "Nine hundred forty-eight" is 948.

Q17. Write the numeral for the following number names.

one thousand and sixty-seven =The numeral for "one thousand and sixty-seven" is 1067.

Q18. Write the numeral for the following number names.
three thousand and sixty-seven =The numeral for "three thousand and sixty-seven" is 3067.

Q19. IN REPEATED ADDITION FORM

5 times 4 =
Ans. In repeated addition form, "5 times 4" means adding 4 five times:

4+4+4+4+4=20

Q20. IN MULTIPLICATION FORM 5 times 4

In multiplication form, "5 times 4" is represented as:

5×4=20

Q 21 Fill in the missing numbers in the following number patterns:

(a)121 , 110 , -------, 88 , ------- , ------- , ------, 44 , ------ , ------

(b) 48 , ------- , -------, -------- , ------- , ----- , 24 , ------ , 16 , 12

ans. Let's find the missing numbers in each pattern:

(a) Pattern: 121, 110, __, 88, __, __, __, 44, __, __

The pattern seems to be decreasing by 11 each time. So, let's fill in the missing numbers:

121 - 11 = 110
110 - 11 = 99
99 - 11 = 88
88 - 11 = 77
77 - 11 = 66
66 - 11 = 55

So, the completed pattern is:
121, 110, 99, 88, 77, 66, 55, 44, 33, 22

(b) Pattern: 48, __, __, __, __, __, 24, __, 16, 12

The pattern seems to be decreasing by 6 each time. So, let's fill in the missing numbers:

48 - 6 = 42
42 - 6 = 36
36 - 6 = 30
30 - 6 = 24
24 - 6 = 18

So, the completed pattern is:
48, 42, 36, 30, 24, 18, 24, 20, 16, 12

The pattern seems to be increasing by 24, then by 22, and then by 12.

11 + 24 = 35
35 + 22 = 57
57 + 12 = 69

Now, let's continue the pattern:

69 + 24 = 93
93 + 22 = 115
115 + 12 = 127

So, the completed pattern is:
11, 35, 57, 69, 93, 115, 127, 139, 151, 163

Q21. Extend the given sequence
25e,30f, 35g,_____,________

Ans. The given sequence appears to be increasing by 5 each time and also changing the alphabet by one step. So, following this pattern:

25e + 5 = 30f
30f + 5 = 35g
To extend the sequence, we add 5 to the previous number and increment the alphabet by one step each time:

35g + 5 = 40h
40h + 5 = 45i
So, the extended sequence would be:

25e,30f,35g,40h,45i

Q22. What will you use, g or kg, to measure the weight of the following:

a) A pencil ________________________
b) A big watermelon _______________________

Ans. To measure the weight of objects:

a) A pencil: It is very light, so we would typically use grams (g) to measure its weight.

b) A big watermelon: It is relatively heavy, so we would typically use kilograms (kg) to measure its weight.

Q23. Fill in the blanks
a) 3300 ml = _____L ________ml
b) 9 L 450 ml = _______ ml

Ans.
a) 3300 ml = 3 L 300 ml
b) 9 L 450 ml = 9450 ml

Q24. Write the number name of the following
a) 2009 ___________________________________________
b) 3169 _______________________________________________
a) 2209 ___________________________________________
b) 4169 _______________________________________________
a) 2129 ___________________________________________
b) 5149 _______________________________________________

Ans.
For number names:
a) 2009 is "two thousand nine"
b) 3169 is "three thousand one hundred sixty-nine"

a) 2209 is "two thousand two hundred nine"
b) 4169 is "four thousand one hundred sixty-nine"

a) 2129 is "two thousand one hundred twenty-nine"
b) 5149 is "five thousand one hundred forty-nine"

Q24. Find the sum of the following
1. Rs 35.50 and Rs 18.00
2. Rs 38.50 and Rs 19.00
3. Rs 45.50 and Rs 28.00
4. Rs 365.50 and Rs 118.00
5. Rs 305.50 and Rs 18.00
6. Rs 65.50 and Rs 18.00
7. Rs 75.50 and Rs 18.00
8. Rs 85.50 and Rs 18.00

Ans. To find the sum of each pair of amounts:

1. Rs 35.50 and Rs 18.00: 35.50 + 18.00 = Rs 53.50
2. Rs 38.50 and Rs 19.00: 38.50 + 19.00 = Rs 57.50
3. Rs 45.50 and Rs 28.00: 45.50 + 28.00 = Rs 73.50
4. Rs 365.50 and Rs 118.00: 365.50 + 118.00 = Rs 483.50
5. Rs 305.50 and Rs 18.00: 305.50 + 18.00 = Rs 323.50
6. Rs 65.50 and Rs 18.00: 65.50 + 18.00 = Rs 83.50
7. Rs 75.50 and Rs 18.00: 75.50 + 18.00 = Rs 93.50
8. Rs 85.50 and Rs 18.00: 85.50 + 18.00 = Rs 103.50

Q25.Find the difference
1. 8 L 635 ml - 4 L 276 ml

9 L 635 ml - 4 L 276 ml
5 L 635 ml - 4 L 276 ml
6 L 635 ml - 4 L 276 ml
82 L 635 ml - 4 L 276 ml
11 L 635 ml - 4 L 276 ml

Ans. To find the difference between each pair of amounts:

1. 8L635ml−4L276ml= 8635 ml−4276ml = 4359ml4359ml

2. 9L635ml−4L276ml= 9635ml−4276ml=5359ml

3. 5L635ml−4L276ml= 5635ml−4276ml= 1359ml

4. 6L635ml−4L276ml= 6635ml−4276ml= 2359ml

5. 82L635ml−4L276ml= 82635ml−4276ml= 78359ml
6. 11L635ml−4L276ml= 11635ml−4276ml= 7359ml

Q26. 328 divided by 8 Check Division

Ans.
To check the division of 328 by 8:

Dividend = 328
Divisor = 8

Quotient × Divisor + Remainder=Dividend

Let's perform the division:
328÷8=41
with a remainder of 0
328÷8=41 with a remainder of 0

Now, let's check:

41×8+0=328

Since the product of the quotient (41) and the divisor (8) equals the dividend (328), the division is correct.

Q27. An almirah has three shelves and each shelf has 5 books. Find out the total number of books in Almirah.
Ans.
If each shelf has 5 books, and there are 3 shelves in total, then the total number of books in the almirah can be found by multiplying the number of books per shelf by the number of shelves.

Number of books per shelf = 5
Number of shelves = 3

Total number of books = Number of books per shelf × Number of shelves
= 5 × 3= 15

So, there are 15 books in the almirah.

Q28. Reetu has 41 kg of potatoes,6 kg of onion, and 25 Kg of tomatoes. How many kilograms of vegetables does she have in total?
Ans. To find the total kilograms of vegetables Reetu has, we simply need to add the weights of potatoes, onions, and tomatoes together.

Potatoes = 41 kg
Onions = 6 kg
Tomatoes = 25 kg

Total kilograms of vegetables = Potatoes + Onions + Tomatoes
= 41 kg + 6 kg + 25 kg
= 72 kg

So, Reetu has a total of 72 kilograms of vegetables.

Q29. The cost per item is given below.
Pencil = Rs 6, Eraser = Rs7 , Note book = Rs 15,
Colour box = Rs 14.50, toffee = Rs2, lemon juice = Rs 4
If you buy each of the above items and give Rs. 50 to the shopkeeper, how much money will you get back?

Ans. To find out how much money you will get back after buying each item, we first need to calculate the total cost of all the items you're purchasing.

The cost of each item:

Pencil = Rs 6
Eraser = Rs 7
Notebook = Rs 15
Colour box = Rs 14.50
Toffee = Rs 2
Lemon juice = Rs 4
Total cost = Rs (6 + 7 + 15 + 14.50 + 2 + 4)
= Rs 48.50

You give Rs 50 to the shopkeeper. So, the money you get back is:

The money you get back = the Amount you gave − Total cost

The money you get back=Rs50−Rs48.50
The money you get back= (1.50)
Money you get back =Rs(1.50)

Since you're giving less money than the total cost, you won't get any money back. Instead,

you will need to pay an additional Rs 3.50 to cover the total cost of all the items.