Self -inductance of a solenoid
Groups:
Group 01 | Emir Can GÜL, Barış BİLGİN, Çağla UĞURAL |
Group 02 | Yiğitcan KOÇAK, Fırat KOÇ |
Group 03 | Beyza DOKTUR, Emir Can KOÇ |
Group 04 | Alara URAL, Pervin ARSLAN, Yasemin ŞEKER |
Group 05 | Feramuz CESUR, Erhan BALCI, Yunus Emre ÇELİK |
Measurement of self-induction coefficient of solenoid:
Date of measure 13:00-08.05.2019
Tools:
Solenoid, power supply, connecting cables, ammeter, voltmeter, ruler, stopwatch.
Measurement method and theoretical knowledge:
When the electric current is passed through the selenode, a magnetic field is formed inside and outside. The solenoid forms an artificial magnet. When we increase or decrease the current passing through the solenoid, the solenoid produces self-induction emf (self-induction current). The resistance of the solenoid to this current is proportional to the self-induction coefficient of selenoin (L)
Method for measurement:
- We set up the electrical circuit consisting of power supply, solenoid, ammeter and voltmeter.
- By opening the switch we have determined the current and voltage values. with the switch on, we measured the time until the current was fixed.
- We closed the switch and measured the time until the current was zero.
- We have averaged both periods.
- We have calculated the values of L = -V.
t / 
and calculated the self-induction coefficient.
We measured the self-induction coefficient by measuring the dimensions of the solenoid.
a) We measured the size of the solenoid.
b) We've determined the number of windings.
c) We calculated the cross-sectional area by measuring its radius.
d) We calculated the self-induction coefficient using L = 
N2.A / l formula. We took = 4
.10-7 N/A2 when calculating this.
We compared the results we found.
Magnet suspended in solenoid magnetic field ...
Our measurements:
The self-induction coefficient found by using L = -V. | ||||
Group | V (volt) |
|
| L (H) |
Group 01 | 8,0 | 0,43 | 4,0 | 0,86 |
Group 02 | 5,8 | 0,35 | 2,5 | 0,81 |
Group 03 | 8,5 | 0,43 | 3,8 | 0,96 |
Group 04 | 11,2 | 0,49 | 5,2 | 1,05 |
Group 05 | 3,5 | 0,32 | 1,6 | 0,70 |
Variance:
Average self-induction coefficient L: 0,876
H
Self-induction coefficient calculated by measuring dimensions
=4.
10-7 =12,56.10-7 N/A2
N=400
l=16.10-2 m
A=.r2=2.10-3 m2
L=N2A/l
L=25,12.10-4 H
Since the length (l) of the solenoid is not much larger than the radius r, we can say that L is incompatible with the value in the experiment.
Conclusion and discussion :
The self-induction coefficient of the solenoid can be determined by various methods. We have used two methods here. We found that the values we determined were compatible with both methods. The difference is due to our measurements and the neglect of some parameters ...
Uvidíme se ...
Mehmet Taşkan
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