Comcategories and Multiorders
May 30, 2015
Multiorders are related to comcategories (co-multi-categories) in the same way that partial orders (posets) are related to categories. There is no consensus in the literature concerning the intended meaning of “multicategory”, and the algorithmic complexity involved in our new formulation is also regrettable. While the fundamental equivalence between decompositions and contractions of triangles in multiorders can be discussed in many ways, the program established here is intended to be sufficient to the exhaustion of that discussion. Our many applications and examples come primarily from the domain of enumerative combinatorics.
denotes the set of all non-empty finite sequences of elements of a set
while
denotes the set of all finite non-empty weakly-increasing sequences of elements of a totally ordered set
The contents of square-brackets may comprise either sets, sequences, or multisets. The two special symbols
have the following meanings.
A comcategory is comprised of a totally ordered set
of objects, a set
of multiarrows with two functions
whose dual image may be summarized
and a multiproduct having the following character of a composition operation. A pair
is composable if
and the set of all composable pairs is denoted . Composition is a function
for which we use the notation
when this is not ambiguous. Naturally one should have
where connotes the obvious transformation
If is a sequence of multiarrows, define a (strict) total ordering relation
on the index set
by letting
iff
or
and
If is the
-ordered sequence of indices, we define the semi-ordering
to be the reordering
The comcategory analogue of associativity is imposed by the multiproduct axiom
apprised for every pair such that
Equivalently,
Given a totally-ordering of the object-set, any multicategory, symmetric or non-symmetric, can be made into an equivalent comcategory. For example, assume is a totally ordered set of objects. The comcategory of rooted sequences has a multiarrow
for every pair Formally constructing the multiproduct of composable pairs and verifying the multiproduct axiom would be a difficult surgery, but the following picture may be entirely satisfying.
A multiorder is a comcategory satisfying the following conditions.
A triangle is a triple satisfying the following three (obvious) boundary conditions.
Notice that the set of all triangles in a comcategory
does not depend on the particular multiproduct (composition) operation, and in the case of multiorders a triangle is simply a composable pair together with its multiproduct (ie.
).
It is useful and traditional to suppose a (multi)arrow in a (com)category to belong to the common domain of two functions (viz. and
), and we will prefer to regard triangles in comcategories in the same way. Hence the meaning of our three pseudo-functions (composite, domain, codomain) will be such that
for all
A decomposition is a pair
A contraction is a pair
The set of decompositions and the set of contractions, both of which involve only triangles in are denoted
and
respectively.
Suppose is a multiorder. If
define two functions
Noting that is a contraction, it remains to construct two more functions
and
so that these four maps together comprise inverse bijections
Suppose Since the sequence
is a permutation of
there is at least one way to choose, for each entry
of
a subsequence
of
such that
is a sequence of triangles for which
is a permutation of
Moreover there is a unique such choice (this is the hard part of the proof) satisfying
namely
We then have
To summarize with a picture, let be the set of all quadruples
where
is a contraction in bijection with a decomposition
. Writing
for all we have the following commutative diagram.
If a triangle in a multiorder is regarded as a morphism
or as a multiarrow
then the composable pairs, whether for morphisms of a category or for multiarrows of a comcategory, are respectively all pairs for
and all pairs
for
Setting
completes the definitions of a contraction category of a multiorder, and of a decomposition comcategory of a multiorder. Compare the well-known constructions of left and right comma-categories.
For any multiarrow of a multiorder
the subset of triangles
is a finite partially ordered set with unique minimum and maximum (but not in general a lattice), where the ordering relation is given by
iff for some
we have
The lattice-form of a multiorder is the indexed family of posets
Let be the set of rational-valued functions with domain
. We call
a lattice-form map and denote its arguments by subscripts
For
we have a binary operation
defined by
The correspondence between contractions and decompositions ensures that this operation is associative, and makes into an algebra which we call the incidence algebra of
. Moreover the presence of minimum and maximum triangles means that any lattice-form map that is nonzero on all unit arrows has a compositional inverse. The Möbius function
is the compositional inverse of
where
for all
Compare the well-known constructions of the incidence algebra and Möbius function of a poset. Our (new) Möbius function of a multiorder is related to the (old) Möbius function on intervals of the lattice-form posets by
for all
Let be the set of positive integers. For
let
be a multiarrow
The multiorder
then has a unique arrow
for each finite multiset of positive integers. It is easy to see that a distinct triangle
exists for each sequence
of multisets of positive integers whose sequence of minima is weakly increasing. The contraction category
then has a morphism
:
for every such triangle This is the simplest known category of multisets. An example of a morphism of
is the following.
The following is a picture of the (truncated) lattice-form of
Let be the Möbius function of
If
then
is equal to the number of distinct permutations of the multiset
Assuming is a totally ordered set, the multiorder of pointed multisets
has a multiarrow
for each pair
with
. For any pair
with
we have a triangle
The following is a picture of a sub-poset of the lattice-form of
An integer partition of is any finite weakly decreasing sequence of positive integers where
denotes the reverse-ordered set of positive integers. Let
be the obvious multiorder of integer partitions, where
For each sequence of integer partitions whose sequence of sums
is weakly decreasing, we have a unique triangle
The following picture shows all morphisms of the contraction category of restricted to
, arranged in a matrix according to source and target.
The following two pictures show the lattice form posets and
A multisystem is a pair where
is a totally ordered set and
is a set of “multiedges”
A multisystem is said to be transitive iff its edges are the multiarrows of a multiorder, where we make the obvious identification
A multisystem
is said to be partitive iff for every pair
satisfying
and
, we have
The definition of the set
of triangles, and of the sets
and
of contractions and decompositions, are generalized from multiorders to multisystems in the obvious way.
A multisystem is said to be contractible iff for all
we have
this implies that the injection
is well-defined. Dually, a multisystem is said to be decomposable iff the inverse injection
is well-defined on
with image contained in
Note that any transitive multisystem is contractible, and any partitive multisystem is decomposable.
Let be the set of positive integers with the usual total ordering. Each of the following four cases defines a contractible and decomposable multisystem
A clutter is a finite connected spanning hypergraph
where no edge
is a subset of any other edge. Let
be the multisystem of all clutters, where
Without loss of generality, we may assume that is the set of all finite subsets of positive integers, ordered lexicographically. The reader should be able verify that
is neither transitive nor partitive, but is contractible. That
is not decomposable is somewhat more difficult to demonstrate (please consult the author’s article on the subject).
Strict partitions
A strict partition is any finite set of positive integers, traditionally sorted in decreasing order. Letting
be the reverse-ordered set of positive integers, and
the set of all strict partitions
It is not hard to show that
is neither transitive nor partitive, but is decomposable. That
is not contractible follows from the observation that, if
is the decomposition given by
then one must have
If is a finite set, let
be the free abelian group generated by the symbols
We have a chain of boundary homomorphisms
and it seems that this construction can be extended inductively in a very natural way. It would be interesting to construct, describe, and characterize the homology groups of multiorders
The author is not supported by academia in any way, and this work was made possible only through considerable ongoing medical and financial support from the United States’ mental health system.