UNIT SIX: PERCENT RELATIONSHIPS Give me 110% effort! | |
Big Idea | |
Proportional relationships can be used to solve real-world problems. | |
Enduring Understandings | |
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Essential Questions | |
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Common Core Standards: Content & Skills | |
Analyze proportional relationships and use them to solve real-world and mathematical problems. | |
7.RP.2 | Recognize and represent proportional relationships between quantities. |
7.RP.3 Visit: Visit: | Use proportional relationships to solve multistep ratio and percent problems. Examples: simple interest, tax, markups and markdowns, gratuities and commissions, fees, percent increase and decrease, percent error. Students should be able to explain or show their work using a representation (numbers, words, pictures, physical objects, or equations) and verify that their answer is reasonable. Models help students to identify the parts of the problem and how the values are related. For percent increase and decrease, students identify the starting value, determine the difference, and compare the difference in the two values to the starting value. Examples:
A student might say: “The original cost of a gallon of gas is $4.17. An increase of 100% means that the cost will double. I will also need to add another 24% to figure out the final projected cost of a gallon of gas. Since 25% of $4.17 is about $1.04, the projected cost of a gallon of gas should be around $9.40.” $4.17 + 4.17 + (0.24 ∙ 4.17) = 2.24 x 4.17
The discount is 33% times 37.50. The sale price of the sweater is the original price minus the discount or 67% of the original price of the sweater, or Sale Price = 0.67 x Original Price.
The sale price is 60% of the original price. This reasoning can be expressed as 12 = 0.60p. Dividing both sides by 0.60 gives an original price of $20.
Solution: The sales team members need to sell the 48 and an additional 30% of 48. 14.4 is exactly 30% so the team would need to sell 15 more TVs than in April or 63 total (48 + 15).
Solution: $2,000 - $500 = $1,500 or the amount needed to be earned as commission. 10% of what amount will equal $1,500. Because 100% is 10 times 10%, then the commission amount would be 10 times 1,500 or 15,000.
Solution: The amount paid = 0.20 x $52.50 + 0.08 x $52.50 = 0.28 x $52.50 or $14.70 for the tip and tax. The total bill would be $67.20,
Solution: One possible solution path follows: $9.18 represents 100% of the cost of the earrings + 8% of the cost of the earrings. This representation can be expressed as 1.08c = 9.18, where c represents the cost of the earrings. Solving for c gives $8.50 for the cost of the earrings.
Notice that the distributive property is implicitly involved in working with percent decrease and increase. For example, in the first problem, if x s the original price of the skateboard (in dollars), then after the 20% discount, the new price is x −20%•x . The distributive property shows that the new price is 80%•x : x − 20%•x = 100%•x − 20%•x = (100% − 20%)x = 80%•x |