Test Review for Ch 2-4

1. For each situation below, sketch 3 graphs: i) position-time, ii) velocity-time, iii) acceleration-time

1. Constant positive acceleration
2. Constant negative acceleration
3. Constant positive velocity
4. Constant negative velocity
5. Stationary object

2. A bullet is shot upward with an initial velocity of 98.0 m/s.

1. Find the displacement of the bullet (from 0 each time) from o to 10.0 s.  Complete the table below.

2. Make a displacement-time graph.  Use graph paper and draw a smooth curve through the dots.
3. Use the graph to estimate the instantaneous velocity of the bullet at 6.00 s.
4. Calculate the instantaneous velocity of the bullet at 6.00 s.
5. When does the bullet reach the point from which it was fired?

3. Use the information from the table below.

6. Draw a velocity-time graph.  Connect the dots with straight-line segments.
7. Find acceleration of the object at the following times:

1. 1.00 sec        ii.  5.00 sec        iii.  9.00 sec        iv.  13.00 sec

8. Find the displacement of the object:

1. from 0 to 2.00 sec                ii.  from 2.00 to 6.00 sec

9. What is the average velocity of the object from 0 to 10.00 seconds?

4. An inconsiderate child drops their gum from the top of a stairwell and it hits Mr. Crites in the head 2.85 s later.

1. How far did the piece of gum fall?
2. With what velocity did the gum strike Mr. Crites?

5. How far does a train travel if it is accelerated from 15 m/s to 125 km/h in 0.75 minutes?

6. A bowling ball traveling at 22.5 m/s experiences an acceleration of –3.55 m/s2.  How far does the ball travels before stopping?

7. A slingshot shoots a marble vertically and rises to 75 m above the point it is shot from.

1. With what velocity did the marble leave the slingshot?
2. How long does it take the marble to come back to the height it was shot?

8.  Mr. DeHorn is jogging with an initial speed of 1.8 m/s and accelerates to a speed of 3.4 m/s in a distance of 13 m.  What was Mr. DeHorn’s acceleration?

9. You are planning a trip to Traverse City, which is 270. km away.  You want to average 100. km/hr for the entire trip.  You go 47.0 km/hr for 1.25 hrs.  How fast do you need to go the rest of the way?

Answer Key:

1.  See teacher key
2. a) 0 s = 0 m; 2 s = 176 m; 4 s = 314 m; 6 s = 412 m; 8 s = 470. m; 10 s = 490. m

        b)  

        c) ~37.4 m/s

        d) 39.2 m/s

        e) 20.0 s

      3.   a)

        b) i) 0 m/s2; ii) 1.00 m/s2; iii) -2.50 m/s2; iv) 2.00 m/s2

        c) i) 12.0 m; ii) 32.0 m

        d) 6.40 m/s

     4.    a) -39.8 m

        b) -27.9 m/s

     5.          1120 m

     6.          71.3 m

     7.        a) 38.3 m/s

        b) 7.82 s
    8.        0.320 m/s2

     9        146 km/hr